python - 将字典变量放入列表 - 打乱它们 - 将它们分成两个嵌套的字典
问题描述
基本上我已经将定义的字典变量放入一个列表中,以便用 random.shuffle 对它们进行洗牌。
现在我想将前 10 个变量导入到 deck1 中,它是一个空的嵌套字典,并将最后 10 个变量导入到 deck2 中,它也是一个空的嵌套字典(我也不知道如何制作一个空的嵌套字典)。
所以本质上程序应该洗牌(这是字典),然后将这些变量放入一个列表中然后洗牌,然后将洗牌的牌分成两个嵌套字典。
import random
deck1={}
deck2={}
theHatefulEight = {"SPECIAL":0, "SPEED": 17, "KNOWLEDGE":90, "STRENGTH":42}
deepBlueSea = {"SPECIAL": 100, "SPEED":50, "KNOWLEDGE":0, "STRENGTH":85}
pulpFiction = {"SPECIAL":100,"SPEED":44, "KNOWLEDGE":98, "STRENGTH":56}
avengersAssemble ={"SPECIAL":50, "SPEED":40, "KNOWLEDGE":100, "STRENGTH":78}
StarWarsEpisodeIII ={"SPECIAL": 100, "SPEED": 97, "KNOWLEDGE": 78, "STRENGTH":100}
snakesOnAPlane = {"SPECIAL":100, "SPEED":100, "KNOWLEDGE":100, "STRENGTH":100}
dieHard = {"SPECIAL":100, "SPEED":29, "KNOWLEDGE":98, "STRENGTH":26}
shaft = {"SPECIAL":100, "SPEED":100, "KNOWLEDGE":99, "STRENGTH":100}
theOtherGuys = {"SPECIAL":100, "SPEED":92, "KNOWLEDGE":90, "STRENGTH":70}
theLegendOfTarzan = {"SPECIAL": 90, "SPEED":94, "KNOWLEDGE":30, "STRENGTH":10}
glass = {"SPECIAL": 100, "SPEED":0, "KNOWLEDGE":80, "STRENGTH":0}
xXx = {"SPECIAL": 89, "SPEED":70, "KNOWLEDGE": 73, "STRENGTH":40}
fourteenOEight = {"SPECIAL": 90, "SPEED": 22, "KNOWLEDGE":100, "STRENGTH":32}
loadedWeapon = {"SPECIAL": 100, "SPEED":77, "KNOWLEDGE":68, "STRENGTH":31}
sphere = {"SPECIAL": 92, "SPEED":12, "KNOWLEDGE":43, "STRENGTH":41}
trueRomance = {"SPECIAL": 10, "SPEED":78, "KNOWLEDGE":1, "STRENGTH":4}
kong = {"SPECIAL": 100, "SPEED":94, "KNOWLEDGE":30, "STRENGTH":10}
coachCarter = {"SPECIAL": 100, "SPEED":30, "KNOWLEDGE":89, "STRENGTH":50}
django = {"SPECIAL": 90, "SPEED":10, "KNOWLEDGE":94, "STRENGTH":18}
jackieBrown = {"SPECIAL": 100, "SPEED":72, "KNOWLEDGE":82, "STRENGTH":84}
print(theHatefulEight)
cards = [theHatefulEight, deepBlueSea, pulpFiction, avengersAssemble,
StarWarsEpisodeIII, snakesOnAPlane, dieHard, shaft, theOtherGuys,
theLegendOfTarzan,
glass, xXx, fourteenOEight, loadedWeapon, sphere, trueRomance, kong,
coachCarter,
django, jackieBrown]
print(cards)
random.shuffle(cards)
print(cards)
````````````````````````
so the program should print the decks:
````````````
deck1 = {"theHatefulEight": {"SPECIAL":0, "SPEED": 17, "KNOWLEDGE":90, "STRENGTH":42},
"deepBlueSea": {"SPECIAL": 100, "SPEED":50, "KNOWLEDGE":0, "STRENGTH":85},
"pulpFiction": {"SPECIAL":100,"SPEED":44, "KNOWLEDGE":98, "STRENGTH":56},
"avengersAssemble": {"SPECIAL":50, "SPEED":40, "KNOWLEDGE":100, "STRENGTH":78},
"StarWarsEpisodeIII":{"SPECIAL": 100, "SPEED": 97, "KNOWLEDGE": 78, "STRENGTH":100},
"snakesOnAPlane": {"SPECIAL":100, "SPEED":100, "KNOWLEDGE":100, "STRENGTH":100},
"dieHard":{"SPECIAL":100, "SPEED":29, "KNOWLEDGE":98, "STRENGTH":26},
"shaft":{"SPECIAL":100, "SPEED":100, "KNOWLEDGE":99, "STRENGTH":100},
"theOtherGuys":{"SPECIAL":100, "SPEED":92, "KNOWLEDGE":90, "STRENGTH":70},
"theLegendOfTarzan": {"SPECIAL": 90, "SPEED":94, "KNOWLEDGE":30, "STRENGTH":10}}
deck2 = {"glass":{"SPECIAL": 100, "SPEED":0, "KNOWLEDGE":80, "STRENGTH":0},
"xXx":{"SPECIAL": 89, "SPEED":70, "KNOWLEDGE": 73, "STRENGTH":40},
"fourteenOEight":{"SPECIAL": 90, "SPEED": 22, "KNOWLEDGE":100, "STRENGTH":32},
"loadedWeapon":{"SPECIAL": 100, "SPEED":77, "KNOWLEDGE":68, "STRENGTH":31},
"sphere":{"SPECIAL": 92, "SPEED":12, "KNOWLEDGE":43, "STRENGTH":41},
"trueRomance":{"SPECIAL": 10, "SPEED":78, "KNOWLEDGE":1, "STRENGTH":4},
"kong":{"SPECIAL": 100, "SPEED":94, "KNOWLEDGE":30, "STRENGTH":10},
"coachCarter":{"SPECIAL": 100, "SPEED":30, "KNOWLEDGE":89, "STRENGTH":50},
"django":{"SPECIAL": 90, "SPEED":10, "KNOWLEDGE":94, "STRENGTH":18},
"jackieBrown":{"SPECIAL": 100, "SPEED":72, "KNOWLEDGE":82, "STRENGTH":84}}
``````````````
if anyone's wondering the dictionaries are top trump cards and the nested dictionaries are decks.
解决方案
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