首页 > 解决方案 > Django - 管理员中的模型类别错误:“选择一个有效的选择。该选择不是可用的选择之一”

问题描述

所以我正在尝试在 django-admin 中构建一个配方字段。我有一个名为 Model 的类别Meals,我在管理页面上有可供选择的类别,但是一旦我尝试保存我的条目,我就会得到Select a valid choice. Breakfast is not one of the available choices& 阻止我保存任何内容。

我已经尝试将daily_meals值从食谱字段移动到膳食类别并取消注释第一个meal值并评论食谱字段中的第二个值。

我如何在餐食类别中创建新餐食,就像食物类别一样,而列表中已经有预先保存的餐食?

膳食类别

保存后管理错误

这是我的代码:

模型.py

from django.db import models
from django.contrib.auth.models import User
from django.utils import timezone




# Food Category
class Category(models.Model):
    name = models.CharField(max_length=250)
    slug = models.SlugField(max_length=250, unique=True)


    class Meta:
        ordering = ('name',)
        verbose_name = 'category'
        verbose_name_plural = 'categories'

    def __str__(self):
        return self.name

# Meal Category
class Meal(models.Model):
    name = models.CharField(max_length=250)
    slug = models.SlugField(max_length=250, unique=True)



    class Meta:
        ordering = ('name',)
        verbose_name = 'meal'
        verbose_name_plural = 'meals'

    def __str__(self):
        return self.name


# Recipe Field
class Recipe(models.Model):

    title = models.CharField(max_length=200)
    category = models.ForeignKey(Category, on_delete=models.CASCADE,)
    daily_meals = (
        ('Breakfast','Breakfast'),
        ('Brunch','Brunch'),
        ('Elevenses','Elevenses'),
        ('Lunch','Lunch'),
        ('Tea','Tea'),
        ('Supper','Supper'),
        ('Dinner','Dinner'),
    )
    # meal = models.CharField(max_length=100, choices = daily_meals)
    meal = models.ForeignKey(Meal, choices = daily_meals, on_delete=models.CASCADE,)
    ingredients = models.TextField(blank=True)
    directions = models.TextField(blank=True)
    created = models.DateTimeField(auto_now_add=True)
    updated = models.DateTimeField(auto_now=True)
    user = models.ForeignKey(User, on_delete=models.CASCADE)

    def __str__(self):
        return self.title

管理员.py

from django.contrib import admin
from .models import Recipe, Category, Meal



class CategoryAdmin(admin.ModelAdmin):
    list_display = ('name', 'slug')
    prepopulated_fields = {'slug': ('name',)}


admin.site.register(Category, CategoryAdmin)




class MealAdmin(admin.ModelAdmin):
    list_display = ('name', 'slug')
    prepopulated_fields = {'slug': ('name',)}


admin.site.register(Meal, MealAdmin)





class RecipeAdmin(admin.ModelAdmin):
    readonly_fields = ('created',)

admin.site.register(Recipe, RecipeAdmin)

标签: djangodjango-modelsdjango-admin

解决方案


ForeignKey 字段通常不使用选项。选择是从数据库中的内容生成的。如果您自己构造选择,choice[0]则必须是Meal表的有效主键。话虽如此,limit_choices_to如果要将选择限制为某些实例,可以使用该参数:

daily_meals = ['Breakfast', 'Brunch', 'Elevenses', 'Lunch', 'Tea', 'Supper', 'Dinner']
# ...
meal = models.ForeignKey(Meal, limit_choices_to={'name__in': daily_meals}, on_delete=models.CASCADE,)

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