python - Python中的递归等待keyPress

Question

我有一个 CAN 数据日志文件，我根据行号将其分成两个相等的部分。我使用 播放此文件canplayer，观察模拟器上的行为，然后按y/n，其中观察到 y 行为或未观察到 n 行为。

code logic:
 1. split file into two parts based on line numbers or entries.
 2. play file1, observe behavior
 3. if behavior observed, take file1, split into two parts again and follow same procedure

（如果file1中没有观察到行为，请执行以下操作或忽略）

 2*. play file2, observe behavior 
 3*. if behavior observed, take file2, split into two parts again and follow same procedure

我有以下代码：

def runParser(self):
    #get the number of lines in file
    num_lines = sum(1 for line in open(self.fileName))
    print(num_lines)
    if(num_lines % 2 == 0):
        splitLen = num_lines/2
    else:
        splitLen = num_lines/2 + 1

    self.splitFile(splitLen) # successfully splits the file and outputs two new files.
    command = "canplayer -I {}".format(self.out1.name)
    #print(command)
    os.system(command)
    print('Do you see the behaviour? press y/n')
    keyboard.on_press(self.accessBehavior)

def accessBehavior(self,event):
    if event.name == 'y':
        self.fileName = self.out1.name
        self.runParser()

    if event.name == 'n':
        command = "canplayer -I {}".format(self.out2.name)
        print(command)
        os.system(command)
        self.fileName= self.out2.name
        self.runParser()

def splitFile(self, len):
    self.fin = open(self.fileName,'rb')
    self.out1 = open('out{}.log'.format(self.fileCount),'wb')
    self.fileCount+=1 # initialized to zero
    self.out2 = open('out{}.log'.format(self.fileCount),'wb')
    self.fileCount+=1

    count=0
    for line in self.fin:
        count +=1
        if count >= len:
            #write to new file
            self.out2.write(line)
        else:
            self.out1.write(line)

    self.fin.close()
    self.out1.close()
    self.out2.close()

1. 我面临的问题是 ,keyboard.on_press(self.accessBehavior)只等待第一次按下。y/n我希望程序根据运行命令后看到的行为接受多次按下canplayer ..

2. 因此，如果没有观察到该行为，我按下n，并且这些步骤不断重复，直到文件中的所有数据都用完并且文件中只存在一行数据，这会调用该行为。

以下是 CAN 数据文件外观示例：

(1584526791.145716) vcan0 13F#000000050000001F
(1584526791.145719) vcan0 164#0000C01AA8000031
(1584526791.145721) vcan0 17C#0000000010000012
(1584526791.145723) vcan0 18E#00005C
(1584526791.147489) vcan0 183#0000000D0000101D
(1584526791.147526) vcan0 143#6B6B00D1
(1584526791.149458) vcan0 095#800007F400000008
(1584526791.153293) vcan0 166#D0320018
(1584526791.153332) vcan0 158#0000000000000019
(1584526791.153335) vcan0 161#000005500108001C
(1584526791.153337) vcan0 191#010090A1410003
(1584526791.153360) vcan0 244#0000000142
(1584526791.154416) vcan0 133#00000000A7
(1584526791.154447) vcan0 136#000200000000002A
(1584526791.154450) vcan0 13A#0000000000000028
(1584526791.154452) vcan0 13F#000000050000002E
(1584526791.154454) vcan0 164#0000C01AA8000004
(1584526791.156373) vcan0 17C#0000000010000021
 .....
 .....
 .....

标签： pythonkeyboard-eventscan-bus