sql - 将单列转换为多行
问题描述
我的输出如下:
03-19-2020
03-20-2020
03-21-2020
03-22-2020
如何将其更改为显示如下:
v_datecol1 v_datecol2 v_datecol3 ------ v_datecoln
03-19-2020 03-20-2020 03-21-2020 03-04-2020
我提到的 4 个日期作为示例,从今天开始我将有 25 个日期,我需要像上面一样在单独的列中
解决方案
尝试:
with dt_tab as
(
select '03-19-2020' dt from dual union
select '03-20-2020' dt from dual union
select '03-21-2020' dt from dual union
select '03-22-2020' dt from dual
)
select listagg(dt,' ') within group (order by dt) rows_as_columns from dt_tab;
根据您的评论,您可以使用 PIVOT,例如:
with dt_tab as
(
select dt, rownum row_num from
(
select '03-19-2020' dt from dual union
select '03-20-2020' dt from dual union
select '03-21-2020' dt from dual union
select '03-22-2020' dt from dual union
select '03-23-2020' dt from dual union
select '03-24-2020' dt from dual union
select '03-25-2020' dt from dual union
select '03-26-2020' dt from dual union
select '03-27-2020' dt from dual union
select '03-28-2020' dt from dual union
select '03-29-2020' dt from dual union
select '03-30-2020' dt from dual union
select '03-31-2020' dt from dual union
select '04-01-2020' dt from dual union
select '04-02-2020' dt from dual union
select '04-03-2020' dt from dual union
select '04-04-2020' dt from dual union
select '04-05-2020' dt from dual union
select '04-06-2020' dt from dual union
select '04-07-2020' dt from dual union
select '04-08-2020' dt from dual union
select '04-09-2020' dt from dual union
select '04-10-2020' dt from dual union
select '04-11-2020' dt from dual union
select '04-12-2020' dt from dual
)
order by dt
)
select * from
(
select dt_tab.* from dt_tab
)
pivot
(
min(dt) for (row_num) in (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25)
)
;
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