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python - 使用 Matplotlib Python 绘制图形

问题描述

我想以不同的图形打印图形，但所有图形都是重叠的。在这里，我的代码中有一个 for 循环（第三个 for 循环），并且我在size 存储的计数中访问numpyArraysDisplay.sizeand的位置。x

现在第一行计数0 to 44，然后第二行计数，依此类推（大小不固定）。

之后，我将其附加到x一个名为position并绘制图形的列表中，但对于第一行，它完美地保存了图形，但对于第二行，它与同一图中的第一行重叠，依此类推。

但是我想要所有线的所有图表都在不同的图中。我已经显示了重叠图的图形。

我写了下面的代码：

import numpy as np
import csv
from scipy.stats import entropy
from matplotlib import pyplot as plt

position = []
store_entropy = []  # Empty list defined to store the list of entropy
outputfile = open("Output.txt", "w")  # Output file open in write mode for saving the outputs

# Reading the csv file by reader
with open('data.csv', 'r') as file:
    reader = csv.reader(file)
    for line in reader:
        lines = filter(None, line[2:])
        lines1 = ' '.join(lines).split(',')

        # Loop for every rows in the file
        for row in lines1[::]:
            makeOneLine = row.rstrip('\n')
            delimiter = " "
            makeOneLine = delimiter.join(makeOneLine.split(delimiter, 3))
            # Makes Numpy Array of all the lines in the file
            numpyArraysDisplay = np.array(list(makeOneLine.split(" ")))
            # print(numpyArraysDisplay)
            outputfile.write(str(numpyArraysDisplay) + '\n')

            # Loop for defining the first segment of the the Numpy Arrays
            for x in range(numpyArraysDisplay.size):
                part1 = numpyArraysDisplay[:x + 1]  # First segment divide
                strings, counts = np.unique(part1, return_counts=True)
                # Counting the frequency of the words appearing in the file line by line
                CountWordsfrequency = np.array(list(dict(zip(strings, counts)).values()))
                # print(CountWordsfrequency)
                outputfile.write(str(CountWordsfrequency) + '\n')

                # Loop for finding the Probability and Entropy of the dialogue types
                for y in range(0, CountWordsfrequency.size):
                    probability = CountWordsfrequency[y] / part1.size
                    outputfile.write("Probability is : " + str(probability) + '\n')
                ent2 = entropy(counts, base=10)
                outputfile.write("Entropy is \t" + str(ent2) + '\n')
                # Store all the Entropies in a list for further work
                store_entropy.append(ent2)
            # print(store_entropy)
                position.append(x+1)
            print(position)
            plt.figure(figsize=(15, 7))
            plt.plot(position, store_entropy, '-o')
            plt.xlabel("Segmentation Break Point")
            plt.ylabel("Entropy")
            plt.xticks(np.arange(0, len(position) + 1, 1))
            plt.savefig('Plots/', figurewidth='25cm')
            plt.show()
            plt.clf()
size = len(store_entropy)
# One Line for loop and if condition to slipt the list by particular values as
# we have to give list inside list for passing particular index of entropy
idx_list = [idx for idx, val in enumerate(store_entropy) if val == 0.0]
res = [store_entropy[i: j] for i, j in zip([0] + idx_list, idx_list + ([size] if idx_list[-1] != 
size else []))]
# print(res)
# for loop and if condition for setting the lists of the Entropies index starting
# from zero instead of 1 and removing the empty lists created in the lists.
res2 = [x for x in res if x != []]
#print(res2)
# print("The List after Split:" + str(res))
#print(res2[0])

输出如下： 图的重叠图像

但我想要不同图形上的所有图表。

标签： pythonmatplotlib

解决方案

在上述情况下，当我查看我的代码时，我发现如果我想将列表传递给，plt.plot()那么我们可能只传递列表变量。当我们使用 for 循环绘制图形时，它会自动获取索引和值。

我有以下解决方案并取得了结果。

for a, b in enumerate(res2):
    plt.figure(figsize=(15, 7))
    plt.plot(b, '-*', color="red")
    plt.xlabel("Dialogue Act Types")
    plt.ylabel("Entropy")
    plt.xticks(np.arange(0, len(b) + 1, 1))
    plt.savefig('Plots/', figurewidth='25cm')
    plt.show()
    plt.close()

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