python - 类似于列表框的树视图的诅咒选择

Question

过去，我采用 Listbox 值并将它们输入到条目小部件中。现在我需要对树做同样的事情，但我发现的唯一帮助类似于我想要做的事情：在树视图中打印和插入选定的行到 tkinter 条目小部件中对我不起作用。基本上我需要弄清楚如何修改我通常对列表框所做的工作以适用于树。

def dynamicPO(self):
    sql=("""SELECT(cast(Notes as nvarchar(max))) 'PO Number', POPY.AccountCode, POPY.Vendor, Items,FORMAT(([POAmount]),'C0') As 'PO AMOUNT', FORMAT(SUM([DailyCosts].DailyCost),'C0') AS 'COSTS TO DATE',FORMAT(POAmount  - SUM(DailyCosts.DailyCost), 'C0') 'Remaining Amount' FROM DailyCosts JOIN POPY ON DailyCosts.WellID = POPY.WellID AND DailyCosts.JobID = POPY.JobID AND (cast(DailyCosts.Notes as nvarchar(max)))= POPY.PONumber WHERE DailyCosts.WellID = ? and DailyCosts.JobID = ? GROUP BY (cast(DailyCosts.Notes as nvarchar(max))),POAmount,POPY.Vendor,POPY.Items,POPY.AccountCode, POPY.WellID, POPY.JobID ORDER BY POPY.Vendor""")
    self.cursor.execute(sql,[self.powellid_bx.get(),self.pojobid_bx.get(ACTIVE)])
    rows = self.cursor.fetchall()
    for row in rows:
        print(row) # it print all records in the database
        self.tree.insert("", tk.END, values=row)

    self.tree= ttk.Treeview(self.tab4, column=("column1", "column2", "column3","column4", "column5", "column6", "column7"), show='headings')
    self.tree.grid(row=7, column = 0, columnspan =8, sticky = "NSEW")
    self.tree.heading("#1", text="PO Number")
    self.tree.heading("#2", text="Budget Code")
    self.tree.heading("#3", text="Vendor")
    self.tree.heading("#4", text="Items")
    self.tree.heading("#5", text="PO Amount")
    self.tree.heading("#6", text="Cost to Date")
    self.tree.heading("#7", text="Remaining PO Amount")

    self.tree.bind("<<TreeViewSelect>>", self.get_selected_PO)

下面的代码适用于列表框，但不幸的是树没有 curselection 选项

def get_selected_PO(self,event):
    global selected_tuple
    if self.tree.curselection():
        index = self.tree.curselection()[0]
        selected_tuple = self.tree.get(index)
        self.treepo_entry.insert('end', str(selected_tuple[0]))
        self.treevend_entry.insert('end', selected_tuple[1])
        self.treeitems_entry.insert('end', selected_tuple[2])
        self.treeamount_entry.insert('end', selected_tuple[3])
        self.treedate_entry.insert('end', selected_tuple[4])
        self.treecomments_entry.insert('end' , selected_tuple[5])

我已经尝试做这样的事情但无济于事

def get_selected_PO(self,event):
    for item in self.tree.selection():
        self.treepo_entry.insert(END,'row')

标签： pythontkintertreeviewtkinter-entry

Answer 1

根据文档，该selection方法将为您返回所选元素的标识符列表。即使您只支持一个选择，这也将是一个列表。

同样根据文档，您可以使用该item方法以字典的形式获取项目的所有信息。

最后，当用户选择一个项目时生成的事件是<<TreeviewSelect>>. 请注意，v是小写的。

这是完整的工作示例：

import tkinter as tk
from tkinter import ttk

class Example:
    def __init__(self):
        root = tk.Tk()
        self.tree = ttk.Treeview(root, columns=("Column1", "Column2"))
        eframe = ttk.Frame(root)
        eframe.pack(side="bottom", fill="x")
        self.tree.pack(side="top", fill="both", expand=True)

        self.e1 = ttk.Entry(eframe)
        self.e2 = ttk.Entry(eframe)
        self.e3 = ttk.Entry(eframe)

        self.e1.pack(side="left", fill="x", expand=True)
        self.e2.pack(side="left", fill="x", expand=True)
        self.e3.pack(side="left", fill="x", expand=True)

        for i in range(10):
            self.tree.insert("", "end", text=f"Item #{i}", values=(f"{i}: a", f"{i}: b"))

        self.tree.bind("<<TreeviewSelect>>", self.handle_selection)

    def handle_selection(self, event):
        self.e1.delete(0, "end")
        self.e2.delete(0, "end")
        self.e3.delete(0, "end")

        selection = self.tree.selection()
        if selection:
            item = self.tree.item(selection)
            self.e1.insert(0, item['text'])
            self.e2.insert(0, item['values'][0])
            self.e3.insert(0, item['values'][1])

Example()
tk.mainloop()