首页 > 解决方案 > 如何进一步融合数据集?

问题描述

我正在处理以下数据:

#Reproducible Example
Bills <- c("93-HCONRES-106", "93-HCONRES-107", "93-HCONRES-108")
Members <- c("00134", "00416;00010;00017;00026", "00416;00503;00513;00568")

data <- data.frame(Bills, Members)

数据如下所示:

#Data Structure
            Bills                 Members
1 93-HCONRES-106                   00134
2 93-HCONRES-107 00416;00010;00017;00026
3 93-HCONRES-108 00416;00503;00513;00568

我想要的是扩展数据集,以便每个账单对应于每个成员。所以数据看起来像这样:

        Bills           Members
93-HCONRES-106          00134
93-HCONRES-107          00416
93-HCONRES-107          00010
93-HCONRES-107          00017
93-HCONRES-107          00026
93-HCONRES-108          00416
93-HCONRES-108          00503
93-HCONRES-108          00513
93-HCONRES-108          00568

您可以分享的任何代码将不胜感激。

非常感谢你们的帮助

标签: rreshapedata-manipulationmelt

解决方案


我们可以separate_rows使用tidyr

library(dplyr)
library(tidyr)
data %>% 
     separate_rows(Members)
#         Bills Members
#1 93-HCONRES-106   00134
#2 93-HCONRES-107   00416
#3 93-HCONRES-107   00010
#4 93-HCONRES-107   00017
#5 93-HCONRES-107   00026
#6 93-HCONRES-108   00416
#7 93-HCONRES-108   00503
#8 93-HCONRES-108   00513
#9 93-HCONRES-108   00568

或者将元素提取到 alist然后unnest

library(stringr)
data %>%
   mutate(Members = str_extract_all(Members, "[^;]+")) %>% 
   unnest(c(Members))

或与base R

stack(setNames(strsplit(as.character(data$Members), ";"), data$Bills))

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