postman - 从提琴手导出到邮递员
问题描述
我正在尝试在 Postman 中模拟这一点。当您单击该按钮时,它会在另一个窗口中打开,因此我无法在 Crome 的开发人员网络工具栏中看到该请求。但是我可以在 Fiddler 中看到它。请求如下所示:
POST http://www.q88.com:8081/ws/API.asmx/GetHVPQQuestions_DataSet HTTP/1.1
Host: www.q88.com:8081
Proxy-Connection: keep-alive
Content-Length: 52
Cache-Control: max-age=0
Origin: http://www.q88.com
Upgrade-Insecure-Requests: 1
Content-Type: application/x-www-form-urlencoded
User-Agent: Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/80.0.3987.149 Safari/537.36
Accept: text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8,application/signed-exchange;v=b3;q=0.9
Referer: http://www.q88.com/ws/API.asmx?op=GetHVPQQuestions_DataSet
Accept-Encoding: gzip, deflate
Accept-Language: en-US,en;q=0.9,da-DK;q=0.8,da;q=0.7,und;q=0.6
Cookie: CompanyID=-1
AuthorizationString=XXXXXXXXXXXXXXXXXXXXXXXXXXXX
现在我希望将其导出到 Postman。但是,由于我无法从 Crome 获得 curl,如何轻松将此原始请求添加到 Postman?
解决方案
导入标题
- Fiddler:文件 > 导出会话 > 选定会话... > cURL 脚本 > 另存为 *.bat > 复制文件内容
- 邮递员>导入>原始文本>粘贴复制的文本
导入正文
- Fiddler > Inspectors > Raw > 复制最后一行的内容
- Postman > Body > raw > 粘贴线
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