首页 > 解决方案 > 将 ImageView 转换为整数:Android Studio

问题描述

我正在尝试获取目标(以 ImageView 开头)id 并将整数 id 放入 switch case 以查看相邻的视图并比较它们的可绘制对象以确定该玩家是否获胜或游戏是否继续。我将 buttonPressed 变量初始化为 Integer 并使用 parseInt() 来获取目标的 int 值。

public void compareButton(int buttonPressed){
    //int count = 0;
    ImageView adjacent;
    ImageView adjacentB;

    switch (buttonPressed){
        case R.id.imageButtonA: //this is where adjacent buttons are identified and compared
            adjacent = findViewById(R.id.imageButtonB);
            adjacentB = findViewById(R.id.imageButtonC);
            if (target.getDrawable() == adjacent.getDrawable() && target.getDrawable() == adjacentB.getDrawable()) {

                Toast.makeText(MainActivity.this, "You Win!", Toast.LENGTH_SHORT).show(); //Win condition


           // } else if (target.getDrawable() == R.id.imageButtonE.getDrawable() & target.getDrawable() == R.id.imageButtonI.getDrawable()) {

                //Toast.makeText(MainActivity.this, "You Win!", Toast.LENGTH_SHORT).show(); //Win condition

           // } else if (target.getDrawable() == R.id.imageButtonD.getDrawable() & target.getDrawable() == R.id.imageButtonG.getDrawable()) {

                //Toast.makeText(MainActivity.this, "You Win!", Toast.LENGTH_SHORT).show(); //Win condition

            }
            break;
        case R.id.imageButtonB:

            break;

我并不是出于调试目的而填写每个案例。

我遇到的问题是,当我运行模拟器时,我收到一条错误消息

Caused by: java.lang.NumberFormatException: For input string: "androidx.appcompat.widget.AppCompatImageButton{517eade VFED..C.. ...P..ID 45,381-304,628 #7f070072 app:id/imageButtonA}"
    at java.lang.Integer.parseInt(Integer.java:521)
    at java.lang.Integer.parseInt(Integer.java:556)
    at com.example.connect3.MainActivity.switchColor(MainActivity.java:75)

这是 OnClickListener 的代码:

public void switchColor(View view) {

    //Button pressed, depending on user, switch's to that users color; identify adjacent button ID's; toast player control switch
    if (player == 1) {

        source = findViewById(R.id.yellow);
        target = findViewById(view.getId());
        target.setImageDrawable(source.getDrawable());
        buttonPressed = Integer.parseInt(target.toString());
        compareButton(buttonPressed);
        player++;
        Toast.makeText(MainActivity.this, "Player 2's Turn!", Toast.LENGTH_SHORT).show();

    } else {

        source = findViewById(R.id.red);
        target = findViewById(view.getId());
        target.setImageDrawable(source.getDrawable());
        buttonPressed = Integer.parseInt(String.valueOf(target));
        compareButton(buttonPressed);
        player--;
        Toast.makeText(MainActivity.this, "Player 1's Turn!", Toast.LENGTH_SHORT).show();

    }

不完全确定此时发生了什么,因为我认为我做的一切都是正确的,但显然遗漏了一些东西。任何帮助,将不胜感激。

标签: javaandroidintegerimageviewparseint

解决方案


改变 :

buttonPressed = Integer.parseInt(String.valueOf(target));

到 :

buttonPressed = target.getId();

解释:您的错误说 NumberFormatException 意味着您正在尝试从无法解析的 String 中获取 int 值,或者简单地说您的字符串不包含正确的 int 值,并且您正在传递 (androidx.appcompat.widget...) 作为字符串,而你必须通过按钮我会


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