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java - Spring Security 中需要授予权限的文本表示

问题描述

我在 Spring Security 中的注册权限有问题
我无法注册方法

我试图设置对每条路径的访问，但没有帮助

控制器

@RestController
public class UserController {

    private UserService userService;

    public UserController(UserService userService) {
        this.userService = userService;
    }

    @PostMapping("/register")
        public Long register(@RequestBody User user){
        return userService.register(user);
    }
}

安全配置 

@Configuration
public class SecurityConfig extends WebSecurityConfigurerAdapter {

    @Bean
    public PasswordEncoder getPasswordEncoder() {
        return new BCryptPasswordEncoder();
    }

    private UserDetailsServiceImpl userDetailsService;

    public SecurityConfig(UserDetailsServiceImpl userDetailsService) {
        this.userDetailsService = userDetailsService;
    }

    @Override
    protected void configure(AuthenticationManagerBuilder auth) throws Exception {
        auth.userDetailsService(userDetailsService);
    }

    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http.csrf().disable();
        http.headers().disable();
        http.authorizeRequests().
                antMatchers("/").permitAll()
                .antMatchers("/register").permitAll();
    }
}

用户服务

@Service
public class UserService {

    private UserRepository userRepository;
    private PasswordEncoder passwordEncoder;

    public UserService(UserRepository userRepository, PasswordEncoder passwordEncoder) {
        this.userRepository = userRepository;
        this.passwordEncoder = passwordEncoder;
    }

    public Long register(User user){
        user.setPassword(passwordEncoder.encode(user.getPassword()));
        userRepository.save(user);
        return user.getId();
    }
}

用户模型

import org.springframework.security.core.GrantedAuthority;
import org.springframework.security.core.authority.SimpleGrantedAuthority;
import org.springframework.security.core.userdetails.UserDetails;

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import java.util.*;

@Entity
public class User implements UserDetails {

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;
    private String userName;
    private String lastName;
    private String password;
    private String role;       

    public User() {
    }

   ..get and set...

    @Override
    public Collection<? extends GrantedAuthority> getAuthorities() {
        List<GrantedAuthority> listRole = new ArrayList<GrantedAuthority>();

        listRole.add(new SimpleGrantedAuthority(role));
        return listRole;
    }

    @Override
    public String getPassword() {
        return password;
    }

    @Override
    public String getUsername() {
        return userName;
    }

    @Override
    public boolean isAccountNonExpired() {
        return true;
    }

    @Override
    public boolean isAccountNonLocked() {
        return true;
    }

    @Override
    public boolean isCredentialsNonExpired() {
        return true;
    }

    @Override
    public boolean isEnabled() {
        return true;
    }
}

错误

java.lang.IllegalArgumentException：在 org.springframework.util.Assert.hasText(Assert.java:284) ~[spring-core-5.2.4.RELEASE.jar:5.2.4.RELEASE] 需要授予权限的文本表示在 org.springframework.security.core.authority.SimpleGrantedAuthority.(SimpleGrantedAuthority.java:38) ~[spring-security-core-5.2.2.RELEASE.jar:5.2.2.RELEASE] 在 com.xxx.xx.models .User.getAuthorities(User.java:71) ~[classes/:na] at java.base/jdk.internal.reflect.NativeMethodAccessorImpl.invoke0(Native Method) ~[na:na] at java.base/jdk.internal .reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) ~[na:na] at java.base/jdk.internal.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) ~[na:na] at java.base /java.lang.reflect.Method.invoke(Method.java:566) ~[na:na]

标签： javaspring-bootspring-security

解决方案

在您的 User 模型类中，确保设置了一个角色，以便您的 getAuthorities() 方法起作用。

您收到的错误提示您正在使用“null”角色执行“新 SimpleGrantedAuthority”。

 @Override
    public Collection<? extends GrantedAuthority> getAuthorities() {
        List<GrantedAuthority> listRole = new ArrayList<GrantedAuthority>();

        listRole.add(new SimpleGrantedAuthority(role)); // this is the problematic line!
        return listRole;
    }

如果您没有角色，则只需返回一个空列表即可。

 @Override
    public Collection<? extends GrantedAuthority> getAuthorities() {
         return Collections.emptyList();
    }

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