javascript - 如何在discord bot上删除所有角色并添加一个角色,然后删除添加的角色并恢复以前的角色
问题描述
我有一行代码让不和谐机器人删除特定的命名角色并在特定时间内添加一个名为“静音”的角色。基本上,服务器只能有 3 个角色,一个可以发出命令,一个具有正常权限的“普通”等级,然后是一个“静音”角色。我的代码专门删除了正常角色并添加了静音角色,因此他们没有任何权限。
好吧,我将我的机器人添加到了具有 3 个以上角色的另一台服务器上,我决定给每个人一个正常的角色,同时也做一个静音的角色。当我运行该命令时,它可以工作,但是由于人们还有其他角色,因此即使静音角色处于最高优先级,它也允许继续发言。
我的问题是,是否有一些代码可以删除他们的所有角色并添加静音角色。并且当静音期结束时,静音角色被删除并恢复他们以前的角色?这是我的代码如下:
case 'mute':
if(!message.member.roles.cache.find(r => r.name === "Admin")) return message.channel.send('You dont have permissions to do that you clown')
let person = message.guild.member(message.mentions.users.first() || message.guild.members.get(args[1]))
if(!person) return message.reply("User Doesn't Exist");
let mainrole = message.guild.roles.cache.find(role => role.name == "normal");
let muterole = message.guild.roles.cache.find(role => role.name == "muted");
if(!muterole) return message.reply("Role Doesn't Exist");
let time = args[2];
if(!time){
return message.reply("How Long?");
}
person.roles.remove(mainrole.id);
person.roles.add(muterole.id);
message.channel.send(`@${person.user.tag} has now been muted for ${ms(ms(time))}`);
setTimeout(function(){
person.roles.add(mainrole.id);
person.roles.remove(muterole.id);
message.channel.send(`@${person.user.tag} has now been unmuted`)
}, ms(time));
break;
case 'help':
const embed2 = new MessageEmbed()
.setTitle("How To Get Commands")
.setColor(0x00fff7)
.setDescription("Do /commands to get the list of commands");
message.author.send(embed2);
break;
解决方案
最简单的方法是从用户那里获取角色列表,清除他们的角色,然后申请 Muted 角色。然后,您需要缓存他们以前的角色,甚至将数据存储在数据库中,以防机器人出现故障,这样一旦重新启动,您就可以获取数据并从中断的地方继续。
这是我即时写的一个简单示例。您可能希望缓存角色的方式与我的方式有所不同,因为我的方法只是为了快速演示,我强烈建议将数据保存到数据库甚至是 .json 文件之类的文件中。
let cachedUserRoles = {};
function addMutedRole(guildId, userId, roleId) {
//Get the guild the user is apart of
let guild = client.guilds.get(guildId);
//Specify the user from the guild
let guildMember = guild.members.get(userId);
//Cache the users existing roles so we can restore them later
cachedUserRoles[userId] = guildMember.roles.cache
//Remove all roles from user
guildMember.roles.set([])
//Add the muted role after all roles have been removed with an array of the single role ID
.then(member => member.roles.add([roleId]))
//Catch and report any errors that might happen
.catch(console.error)
}
function restoreRoles(guildId, userId) {
//Get the guild the user is apart of
let guild = client.guilds.get(guildId);
//Specify the user from the guild
let guildMember = guild.members.get(userId);
//Get and set the user's previouse roles from cachedUserRoles and error log if anything goes wrong
guildMember.roles.set(cachedUserRoles[userId]).catch(console.error)
}
在您的情况下,它看起来像这样:
case 'mute':
if(!message.member.roles.cache.find(r => r.name === "Admin")) return message.channel.send('You dont have permissions to do that you clown')
let person = message.guild.member(message.mentions.users.first() || message.guild.members.get(args[1]))
if(!person) return message.reply("User Doesn't Exist");
let muterole = message.guild.roles.cache.find(role => role.name == "muted");
if(!muterole) return message.reply("Role Doesn't Exist");
let time = args[2];
if(!time){
return message.reply("How Long?");
}
//Cache their already existing roles
cachedUserRoles[person.id] = person.roles.cache;
//Set their roles to an empty array to clear them, then add the muted role once all roles were removed successfully
person.roles.set([]).then(member => member.roles.add(muterole)).catch(console.error);
message.channel.send(`@${person.user.tag} has now been muted for ${ms(ms(time))}`);
setTimeout(function(){
//Grab their existing roles and set them back to the user, we wont need to remove the muted role since setting the roles would override all existing ones already
person.roles.set(cachedUserRoles[person.id]).catch(console.error)
message.channel.send(`@${person.user.tag} has now been unmuted`)
}, ms(time));
break;
case 'help':
const embed2 = new MessageEmbed()
.setTitle("How To Get Commands")
.setColor(0x00fff7)
.setDescription("Do /commands to get the list of commands");
message.author.send(embed2);
break;
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