首页 > 解决方案 > 当值为“”Angular 6时从对象中删除一个属性

问题描述

Remove the property name "referenceNumber" from object "searchParams" when value of "referenceNumber" is "" (empty)


<input #refNumInput  (keyup)="onRefNumKeyUp($event)" [(ngModel)]="searchParams.referenceNumber" type="text" id="referenceNo" name="referenceNo">

请参考上面的代码

标签: data-bindingangular6angular7angular-ngmodel

解决方案


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