首页 > 解决方案 > 如何修复我的麦克风无法正确接收输入的异常错误?

问题描述

我正在以 siri 和谷歌助手的形式构建一个弱 Ai 平台,但是,每次我运行我的代码时,它总是返回“对不起,我没有抓住那个”——这个异常而不是通过我的麦克风接收输入。我是按照 YouTube 教程来构建它,因为我对 python 还很陌生,因此我不知道问题是什么,因为它似乎对教程中的人来说工作正常。有人可以指导我解决这个问题吗?谢谢

import pyttsx3
import speech_recognition as sr
import datetime
import wikipedia
import webbrowser
import os
import smtplib
import pythoncom

print("Initializing Karren")

MASTER = "Nadeem"

engine = pyttsx3.init('sapi5')
voices = engine.getProperty('voices')
engine.setProperty('voice', voices[1].id)

def speak(text):
    engine.say(text)
    engine.runAndWait()


def wishMe():
    hour = int(datetime.datetime.now().hour)

    if hour>=0 and hour <12:
        speak("Good Morning" + MASTER)

    elif hour>=12 and hour<18:
        speak("Good Afternoon" + MASTER)
    else:
        speak("Good Evening" + MASTER)


    speak("How may I assist you?")

def takeCommand():
    r = sr.Recognizer()
    with sr.Microphone() as source:
        print("Listening...")
        audio = r.listen(source)
    try :
        print("Recognizing...")
        query = r.recognize_google(audio, language ='en-uk')
            print(f"user said: {query}\n")

        except Exception as e:
            print("Sorry i didn't catch that...")

speak("Initializing Karren...")
wishMe()
query = takeCommand()

#Logic
if query:
    if 'wikipedia' in query.lower():
        speak('Searching wikipedia...')
        query = query.replace("wikipedia", "")
        results = wikipedia.summary(query, sentences =2)
        print(results)
        speak(results)


    if 'open youtube' in query.lower():
        webbrowser.open("youtube.com")

标签: pythonpython-3.xartificial-intelligencespeech-recognition

解决方案


好吧,这是更新的代码@iSavageSkull

import pyttsx3
import speech_recognition as sr
import datetime
import wikipedia
import webbrowser
import os
import smtplib
import pythoncom

print("Initializing Karren")

MASTER = "Nadeem"

engine = pyttsx3.init('sapi5')
voices = engine.getProperty('voices')
engine.setProperty('voice', voices[1].id)

def speak(text):
    engine.say(text)
    engine.runAndWait()


def wishMe():
    hour = int(datetime.datetime.now().hour)

    if hour>=0 and hour <12:
        speak("Good Morning" + MASTER)

    elif hour>=12 and hour<18:
        speak("Good Afternoon" + MASTER)
    else:
        speak("Good Evening" + MASTER)


    speak("How may I assist you?")

def takeCommand():
    r = sr.Recognizer()
    with sr.Microphone() as source:
        print("Listening...")
        audio = r.listen(source)
    try :
        print("Recognizing...")
        query = r.recognize_google(audio, language ='en-uk')
        print(f"user said: {query}\n")

    except Exception as e:
        print("Sorry i didn't catch that...")

speak("Initializing Karren...")
wishMe()
query = takeCommand()

#Logic
if query:
    if 'wikipedia' in query.lower():
        speak('Searching wikipedia...')
        query = query.replace("wikipedia", "")
        results = wikipedia.summary(query, sentences =2)
        print(results)
        speak(results)


    if 'open youtube' in query.lower():
        webbrowser.open("youtube.com")

您在这里所做的错误:

  1. 在 下def takeCommand()print(f"user said: {query}\n")缩进错误,应该正确缩进。

  2. 同样def takeCommand()的下,

    except Exception as e:
        print("Sorry i didn't catch that...")

这里又是缩进错误,这就是为什么它总是不断打印错误,即使代码产生了合法的输出

运行我更新的你的代码,程序运行良好!!!


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