c - 头部单链表中的元素删除不起作用
问题描述
#include <stdio.h>
#include <stdlib.h>
struct node {
int data;
struct node *next;
};
struct node *head = NULL;
struct node *second = NULL;
struct node *third = NULL;
void insertAtBeg(struct node *n, int data) {
struct node *temp;
temp = (struct node *)malloc(sizeof(struct node));
temp->data = data;
temp->next = head;
head = temp;
}
void insertAtEnd(struct node *n, int data) {
struct node *temp;
temp = (struct node*)malloc(sizeof(struct node));
temp->data = data;
temp->next = NULL;
while (n->next != NULL) {
n = n->next;
}
n->next = temp;
}
void deleteElement(struct node *head, int data) {
if (head->data == data) {
struct node *temp;
temp = head;
head = head->next;
free(temp);
printf("after deletion at head in function\n");
printList(head);
}
}
void printList(struct node *n) {
while (n != NULL) {
printf("%d\n", n->data);
n = n->next;
}
}
void main() {
head = (struct node*)malloc(sizeof(struct node));
second = (struct node*)malloc(sizeof(struct node));
third = (struct node*)malloc(sizeof(struct node));
head->data = 1;
head->next = second;
second->data = 2;
second->next = third;
third->data = 3;
third->next = NULL;
printList(head);
insertAtBeg(head, 0);
printf("after insertion at beginning\n");
printList(head);
insertAtEnd(head, 4);
printf("after insertion at End\n");
printList(head);
deleteElement(head, 0);
printf("after deletion at head in main\n");
printList(head);
}
代码的输出是
1
2
3
after insertion at beginning
0
1
2
3
after insertion at End
0
1
2
3
4
after deletion at head in function
1
2
3
4
after deletion at head in main
0
1
2
3
4
为什么在 main 中调用的函数和在另一个函数中调用的函数的输出存在差异。即在函数中的 head 删除后和 main 中的 head 删除后,当两者都应该从同一个列表中删除元素时
解决方案
问题是在从列表中插入和/或删除元素时,您需要一种修改列表头部的方法。
一个简单的方法是让这些函数返回一个可能更新的头指针值,并让调用者将此返回值存储到它的head
变量中。
这是具有这些语义的代码的修改版本:
#include <stdio.h>
#include <stdlib.h>
struct node {
int data;
struct node *next;
};
struct node *insertAtBeg(struct node *head, int data) {
struct node *temp;
temp = (struct node *)malloc(sizeof(struct node));
// should test for memory allocation failure
temp->data = data;
temp->next = head;
return temp;
}
struct node *insertAtEnd(struct node *head, int data) {
struct node *temp;
struct node *n;
temp = (struct node*)malloc(sizeof(struct node));
// should test for memory allocation failure
temp->data = data;
temp->next = NULL;
if (head == NULL)
return temp;
n = head;
while (n->next != NULL) {
n = n->next;
}
n->next = temp;
return head;
}
struct node *deleteElement(struct node *head, int data) {
// delete the first node with a given data
if (head->data == data) {
struct node *temp = head;
head = head->next;
free(temp);
} else {
struct node *n = head;
while (n->next != NULL) {
if (n->next->data == data) {
struct node *temp = n->next;
n->next = temp->next;
free(temp);
break;
}
}
}
return head;
}
void printList(const struct node *n) {
while (n != NULL) {
printf("%d\n", n->data);
n = n->next;
}
}
int main() {
struct node *head = NULL;
head = insertAtBeg(head, 1);
head = insertAtEnd(head, 2);
head = insertAtEnd(head, 3);
printList(head);
head = insertAtBeg(head, 0);
printf("after insertion at beginning\n");
printList(head);
head = insertAtEnd(head, 4);
printf("after insertion at End\n");
printList(head);
head = deleteElement(head, 0);
printf("after deletion at head in main\n");
printList(head);
// should free the list
return 0;
}
另一种方法是传递列表头指针的地址,以便函数可以在需要时对其进行修改。
这是使用这种替代方法的代码的修改版本:
#include <stdio.h>
#include <stdlib.h>
struct node {
int data;
struct node *next;
};
struct node *insertAtBeg(struct node **headp, int data) {
struct node *temp = malloc(sizeof(*temp));
if (temp != NULL) {
temp->data = data;
temp->next = *headp;
*headp = temp;
}
return temp;
}
struct node *insertAtEnd(struct node **headp, int data) {
struct node *temp = malloc(sizeof(*temp));
if (temp != NULL) {
temp->data = data;
temp->next = NULL;
if (*headp == NULL) {
*headp = temp;
} else {
struct node *n = *headp;
while (n->next != NULL) {
n = n->next;
}
n->next = temp;
}
}
return temp;
}
int deleteElement(struct node **headp, int data) {
// delete the first node with a given data
struct node *head = *headp;
if (head->data == data) {
*headp = head->next;
free(temp);
return 1; // node was found and freed
} else {
struct node *n = head;
while (n->next != NULL) {
if (n->next->data == data) {
struct node *temp = n->next;
n->next = temp->next;
free(temp);
return 1; // node was found and freed
}
}
return 0; // node not found
}
}
void printList(const struct node *n) {
while (n != NULL) {
printf("%d\n", n->data);
n = n->next;
}
}
int main() {
struct node *head = NULL;
insertAtBeg(&head, 1);
insertAtEnd(&head, 2);
insertAtEnd(&head, 3);
printList(head);
insertAtBeg(&head, 0);
printf("after insertion at beginning\n");
printList(head);
insertAtEnd(&head, 4);
printf("after insertion at End\n");
printList(head);
deleteElement(&head, 0);
printf("after deletion at head in main\n");
printList(head);
// free the list
while (head != NULL) {
deleteElement(&head, head->data);
}
return 0;
}
这种替代方法使用双指针,因此初学者理解起来有点困难,但它有一个强大的优势:函数可以更新列表指针并提供有意义的返回值,可以通过测试来检测错误。例如insertAtBeg()
,如果无法分配新节点但保留列表,则insertAtEnd()
返回。NULL
类似地deleteElement()
可以返回一个指示元素是否找到的指示符。
使用这种方法,您可以编写函数来弹出列表的第一个或最后一个元素,或者给定索引处的元素,或者具有给定 的元素data
,同时根据需要更新列表指针。
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