时间戳

首页 > 解决方案 > 如何在 GNU bash 中检查输入是数字还是字母

shell - 如何在 GNU bash 中检查输入是数字还是字母

问题描述

我在 GNU sed 命令中收到错误“如果”然后“”意外。如何连续检查输入。请帮助我

if ! [[ "$versionCode" =~ ^[0-9]+$ ]]
then
    echo "Sorry integers only"
fi

这是我的错误

sh: 1: Syntax error: end of file unexpected (expecting "then")

sh: 1: Syntax error: "then" unexpected

Sorry integers only
sh: 1: Syntax error: "fi" unexpected

更新：

echo "Enter version code" 
read versionCode
case "$versionCode" in
   (*[!0-9]*) echo "Sorry integers only";;
   ("")       echo "Empty is not a version code";;
   (*)        echo "do something with $versionCode";;
 esac
echo "$versionCode"
sudo  sed "s/\(versionCode[[:space:]]*\)[0-9]*/\1${versionCode}/" Version.gradle

这是我的错误

Enter version code
4

sh: 1: Syntax error: end of file unexpected (expecting ")")

sh: 1: Syntax error: word unexpected

sh: 1: Syntax error: word unexpected

sh: 1: Syntax error: word unexpected

sh: 1: Syntax error: "esac" unexpected

标签： shellcarriage-return

解决方案

POSIXly 可移植的方法是

 case "$versionCode" in
   (*[!0-9]*) echo "Sorry integers only";;
   ("")       echo "Empty is not a version code";;
   (*)        echo "do something with $versionCode";;
 esac

推荐阅读