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javascript - PHP注册脚本中的“需要电子邮件”错误

问题描述

我目前正在编写一个执行基本用户注册的脚本。

当用户到达登录页面时，我有一个 JS 脚本，它从 URL 中识别他们的电子邮件并将其填充到电子邮件输入框中（已禁用）。之后，用户只需输入密码即可创建帐户。然而，即使它已被 JS 脚本填充，PHP 也会抛出错误“需要电子邮件”。

我试图将输入框的状态更改为禁用到启用，这并没有多大帮助。我已附上以下过程中涉及的文件。任何帮助将不胜感激。

填写电子邮件.js

$(document).ready(function() {
var link = window.location.href;

var emailIndex = link.indexOf("email");

if(emailIndex != -1) {
link = link.substring(emailIndex + 6);
} else {
    link = "";
}

document.getElementById("email").value = link;
//$('#email').attr('disabled', 'disabled');});

注册.php

<?php include('server.php') ?>

<!DOCTYPE html>
<html>
<head>
  <title>Register</title>
  <link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
  <div class="header">
    <h2>Register</h2>
  </div>

  <form method="post" action="register.php">
    <?php include('errors.php'); ?>
    <div hidden class="input-group">
      <label>Username</label>
      <input type="text" name="username" value="user">
    </div>
    <div class="input-group">
      <label>Email</label>
      <input type="email" name="email" id="email" value="<?php echo $email; ?>" disabled>
    </div>
    <div class="input-group">
      <label>Password</label>
      <input type="password" name="password_1">
    </div>
    <div class="input-group">
      <label>Confirm password</label>
      <input type="password" name="password_2">
    </div>
    <div class="input-group">
      <button type="submit" class="btn" name="reg_user">Register</button>
    </div>
  </form>
</body>
<script
  src="https://code.jquery.com/jquery-3.4.1.js"
  integrity="sha256-WpOohJOqMqqyKL9FccASB9O0KwACQJpFTUBLTYOVvVU="
  crossorigin="anonymous">
</script>
<script type='text/javascript' src="fillEmail.js"></script>
</html>

服务器.php

<?php
session_start();

// initializing variables
$username = "";
$email = "";
$errors = array(); 

// connect to the database
$db = mysqli_connect('localhost', 'root', '', 'registration');

// REGISTER USER
if (isset($_POST['reg_user'])) {
  // receive all input values from the form
  $username = mysqli_real_escape_string($db, $_POST['username']);
  $email = mysqli_real_escape_string($db, $_POST['email']);
  $password_1 = mysqli_real_escape_string($db, $_POST['password_1']);
  $password_2 = mysqli_real_escape_string($db, $_POST['password_2']);

  // form validation: ensure that the form is correctly filled ...
  // by adding (array_push()) corresponding error unto $errors array
  if (empty($username)) { array_push($errors, "Username is required"); }
  if (empty($email)) { array_push($errors, "Email is required"); }
  if (empty($password_1)) { array_push($errors, "Password is required"); }
  if ($password_1 != $password_2) {
    array_push($errors, "The two passwords do not match");
  }

  // first check the database to make sure 
  // a user does not already exist with the same username and/or email
  $user_check_query = "SELECT * FROM users WHERE username='$username' OR email='$email' LIMIT 1";
  $result = mysqli_query($db, $user_check_query);
  $user = mysqli_fetch_assoc($result);

  if ($user) { // if user exists
    if ($user['username'] === $username) {
      array_push($errors, "Username already exists");
    }

    if ($user['email'] === $email) {
      array_push($errors, "email already exists");
    }
  }

  // Finally, register user if there are no errors in the form
  if (count($errors) == 0) {
    $password = md5($password_1);//encrypt the password before saving in the database

    $query = "INSERT INTO users (username, email, password) 
              VALUES('$username', '$email', '$password')";
    mysqli_query($db, $query);
    $_SESSION['username'] = $username;
    $_SESSION['success'] = "You are now logged in";
    header('location: index.php');
  }
}
?>

我对 PHP 相当陌生，所以任何帮助将不胜感激。提前非常感谢！

标签： javascriptphpjquerysqlregistration

解决方案

根据我的评论，您可以简单地使用readonly而不是disabled达到类似的效果。还请使用准备好的语句来防止 SQL 注入。mysqli_real_escape_string是不足够的

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