时间戳

首页 > 解决方案 > 单击按钮时如何减少屏幕上的余额数

python - 单击按钮时如何减少屏幕上的余额数

问题描述

我在屏幕上呈现了值为 100 的文本，当我单击下注按钮时，我希望屏幕上的值减少 10。不知道该怎么做。添加了时钟滴答，因此单击一次时它不会垃圾邮件值更改。我尝试创建一个名为balance_value_change的新变量并将其设置为 0。将 -= 10 替换为balance_value_change = 10然后balance_value -= balance_value_change。我能够让它打印出我想要的东西，但我仍然坚持如何在点击下注按钮时渲染屏幕以刷新新号码。抱歉，解释太长了！

import pygame as pg

pg.init()

screen = pg.display.set_mode((800, 600))
background = pg.image.load('images/sideBar.jpg')
bj_icon = pg.image.load('images/blackjack_aces.png')
clock = pg.time.Clock()

#Sidebar fonts/buttons
font = pg.font.Font('freesansbold.ttf', 18)
blackjack = font.render('BlackJack', True, (255,255,255))
balance_value = 100
balance_value_change = 0
money = font.render('Balance: ' + str(balance_value), True, (255,255,255))

#Button Class
class button():
    def __init__ (self, color, x, y, width, height, text=''):
        self.color = color
        self.x = x
        self.y = y
        self.width = width
        self.height = height
        self.text = text

    def draw(self, screen, outline=None):
        if outline:
            pg.draw.rect(screen, outline, (self.x-2, self.y-2, self.width+4, 
        self.height+4), 0)

        pg.draw.rect(screen, self.color, (self.x, self.y, self.width, 
        self.height), 0)

        if self.text != '':
            font = pg.font.Font('freesansbold.ttf', 18)
            text = font.render(self.text, 1, (190,0,0))
            screen.blit(text, (self.x + (self.width/2 -text.get_width()/2), 
            self.y + (self.height/2 - text.get_height()/2)))

    def isOver(self, pos):
        if pos[0] > self.x and pos[0] < self.x + self.width:
            if pos[1] > self.y and pos[1] < self.y + self.height:
                return True

        return False

def redrawWindow():

    betButton.draw(screen, (0,0,0))
    hitButton.draw(screen, (0,0,0))
    stayButton.draw(screen, (0,0,0))

betButton = button((255,0,0), 625,300,120,25, 'B E T' )
hitButton = button((255,0,0), 625,350,120,25, 'H I T' )
stayButton = button((255,0,0), 625,400,120,25, 'S T A Y' )

running = True
while running:

    screen.fill((0,100,0))
    screen.blit(background, (550,50))
    screen.blit(bj_icon, (625, 50))

    for event in pg.event.get():
        pos = pg.mouse.get_pos()

        if event.type == pg.QUIT:
            running = False

    if event.type == pg.MOUSEBUTTONDOWN and event.button == 1:
        if betButton.isOver(pos):
            balance_value -= 10

    #Mouse Button Hover
    if event.type == pg.MOUSEMOTION:

        if betButton.isOver(pos):
            betButton.color = (125,125,125)
        else:
            betButton.color = (255,255,255)

        if hitButton.isOver(pos):
            hitButton.color = (125,125,125)
        else:
            hitButton.color = (255,255,255)

        if stayButton.isOver(pos):
            stayButton.color = (125,125,125)
        else:
            stayButton.color = (255,255,255)

    redrawWindow()
    screen.blit(money, (625,270))
    screen.blit(blackjack, (640,180))
    clock.tick(15)
    pg.display.update()

标签： pythonbuttonpygameclick

解决方案

减少值是不够的。必须呈现新文本：

if betButton.isOver(pos):
    balance_value -= 10
    money = font.render('Balance: ' + str(balance_value), True, (255,255,255))

此外，它是Indentation的问题。您必须MOUSEBUTTONDOWN在事件循环中而不是在应用程序循环中处理事件：

running = True
while running:

    # [...]

    for event in pg.event.get():
        pos = pg.mouse.get_pos()

        if event.type == pg.QUIT:
            running = False

        #-->| INDENTATION
        if event.type == pg.MOUSEBUTTONDOWN and event.button == 1:
            if betButton.isOver(pos):
                balance_value -= 10
                money = font.render('Balance: ' + str(balance_value), True, (255,255,255))

        if event.type == pg.MOUSEMOTION:

            if betButton.isOver(pos):
                betButton.color = (125,125,125)
            else:
                betButton.color = (255,255,255)

            if hitButton.isOver(pos):
                hitButton.color = (125,125,125)
            else:
                hitButton.color = (255,255,255)

            if stayButton.isOver(pos):
                stayButton.color = (125,125,125)
            else:
                stayButton.color = (255,255,255)

推荐阅读