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python - 解析python字典中相同键的值

问题描述

alice_ratings = {"alonzo": 1, "bob": 3, "turing" : 2}
bob_ratings = {"alice": 1, "alonzo": 2, "turing": 3}
alonzo_ratings = {"alice": 3, "bob": 2, "turing": 1}
turing_ratings = {"alice": 2, "alonzo": 1, "bob": 3}

给了我相应的学生偏好字典，我想写一个函数，返回一个平均分最低的学生，我该怎么做。示例：alonzo 的总体评分为 4，我该怎么做才能有人帮我解决这个问题

标签： pythondictionary

解决方案

IIUC，用途：

def lowest(*args):
    ratings = {}
    for d in args:
        for k, v in d.items():
            if k in ratings:
                ratings[k] += v
            else:
                ratings[k] = v
    return min(ratings, key=lambda k: ratings[k])

或者，

from collections import defaultdict

def lowest(*args):
    ratings = defaultdict(int)
    for d in args:
        for k, v in d.items():
            ratings[k] += v

    return min(ratings, key=lambda k: ratings[k])

调用函数：

print(lowest(alice_ratings, bob_ratings, alonzo_ratings, turing_ratings))

这打印：

alonzo

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