ruby-on-rails - 如何在我的控制器中重构这个 rails 代码？

Question

我目前在我的控制器中有这个：

        @employees = Employee.all
        #need to keep params different because of nested route(id) and filter form params
        if !params[:employee].blank? && !params[:contact].blank?
            @logs = Log.both_filters(params[:employee], params[:contact]).date_ordered
        elsif params[:employee_id] 
            @logs = Log.by_employee(params[:employee_id]).date_ordered
        elsif !params[:employee].blank?
            @logs = Log.by_employee(params[:employee]).date_ordered
        elsif params[:contact_id]
            @logs = Log.by_contact(params[:contact_id]).date_ordered
        elsif !params[:contact].blank?
            @logs = Log.by_contact(params[:contact]).date_ordered
        else
            @logs = Log.all.date_ordered
        end
    end 

我必须设置两个不同的参数，因为索引也是员工和联系人的嵌套路由 (params[:contact_id])，然后我还想将加载与两个过滤器 (params[:contact]) 区分开来。

我为模型中的过滤器设置了参数：

        where(employee: employee_id)
    end 


    def self.by_contact(contact_id)
        where(contact: contact_id)
    end 

它看起来就像我的控制器中有很多逻辑，并且有少量重复。我只在 Ruby on Rails 上，还没有 JS。

先感谢您！

标签： ruby-on-railscontroller

Answer 1

您可以创建一个单独的类来处理它：

class LogFilter
  def initialize(args = {})
    @contact = args[:contact]
    @contact_id = args[:contact_id]
    @employee = args[:employee]
    @employee_id = args[:employee_id]
  end

  def call
    return Log.both_filters(employee, contact).date_ordered      if employee? && contact?
    return Log.by_employee(employee_id || employee).date_ordered if employee_id.present? || employee?
    return Log.by_contact(contact_id   || contact).date_ordered  if contact_id.present?  || contact?

    Log.all.date_ordered
  end

  private

  attr_reader :contact, :employee

  def contact?
    contact.present?
  end

  def employee?
    employee.present?
  end
end