首页 > 解决方案 > 如何在 tkinter 中使用 Entry.get() 函数?

问题描述

我想这样做,所以当您单击确认时,您会收到一条消息,上面写着谢谢您的用户名:然后您输入的用户名可以有人帮我解决这个问题。

from tkinter import *

root = Tk()

e1 = Entry(root)
e1.grid(row = 0, column = 1, pady = 2)
user = e1.get()

e2 = Entry(root)
e2.grid(row = 1, column = 1, pady = 2)

l1 = Label(root, text='Username:')
l1.grid(row = 0, column = 0, pady = 2)

l2 = Label(root, text='Password:')
l2.grid(row = 1, column = 0, pady = 2)

def confirm():
    l3 = Label(root, text='thank you')
    l3.grid(row = 2, column = 1, pady = 2)
    l4= Label(root, text='Your  Username: '+user)
    l4.grid(row  = 3, column = 1, pady =2)

b1 = Button(command=confirm, text='Confirm')
b1.grid(row = 3, column = 0, pady = 2)


root.mainloop()

标签: pythontkinter

解决方案


尝试:

from tkinter import *

root = Tk()
global e1
e1 = Entry(root)
e1.grid(row = 0, column = 1, pady = 2)


e2 = Entry(root)
e2.grid(row = 1, column = 1, pady = 2)

l1 = Label(root, text='Username:')
l1.grid(row = 0, column = 0, pady = 2)

l2 = Label(root, text='Password:')
l2.grid(row = 1, column = 0, pady = 2)

def confirm():
    user = e1.get()
    l3 = Label(root, text='thank you')
    l3.grid(row = 2, column = 1, pady = 2)
    l4= Label(root, text='Your  Username: '+user)
    l4.grid(row  = 3, column = 1, pady =2)

b1 = Button(command=confirm, text='Confirm')
b1.grid(row = 3, column = 0, pady = 2)

输出:

输出


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