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python - 显示字典Python中查询文件中每行单词的次数

问题描述

我有一个 docs.txt 作为文件，注意分开的三行：

joyously urgently truthfully seemingly broadly urgently knowingly urgently steadily
joyously urgently truthfully seemingly rigidly broadly rigidly suddenly healthily commonly often
tremendously totally steadily sharply totally

我有一个带有此文件的querys.txt：

urgently
rigidly suddenly
totally steadily

和代码：

dictionary = {}
    angledictionary={}
    document= open('docs.txt', 'r')
    for line in document:
        lined=line.split()
        for word in lined:
            if word not in dictionary.keys():
                dictionary[word]=0
            dictionary[word]+=1
    dictionary=dict.fromkeys(dictionary,0)
    with open("queries.txt", "r") as open_queries:
        searchquery = open_queries.read().split("\n")
    with open('docs.txt', 'r') as openrelevancy:
        words = openrelevancy.read().split("\n")
    for query in searchquery:
        print('Query:', query)
        relevant = []
        line_number = 0
        for word in words:
            line_number += 1
            if query in word:
                relevant.append(line_number)
        print('Relevant Documents:', *relevant)

现在，每行的字典字数为 0，我正在尝试这样做： FOR LINE 1：

{'joyously': 1, 'urgently': 3, 'truthfully': 1, 'seemingly': 1, 'broadly': 1, 'knowingly': 1, 'steadily': 1, 'rigidly': 0, 'suddenly': 0, 'healthily': 0, 'commonly': 0, 'often': 0, 'tremendously': 0, 'totally': 0, 'sharply': 0}

对于第 2 行：

{'joyously': 1, 'urgently': 1, 'truthfully': 1, 'seemingly': 1, 'broadly': 1, 'knowingly': 1, 'steadily': 1, 'rigidly': 2, 'suddenly': 1, 'healthily': 1, 'commonly': 1, 'often': 1, 'tremendously': 0, 'totally': 0, 'sharply': 0}

对于第 3 行：

{'joyously': 0, 'urgently': 0, 'truthfully': 0, 'seemingly': 0, 'broadly': 0, 'knowingly': 0, 'steadily': 0, 'rigidly': 0, 'suddenly': 0, 'healthily': 0, 'commonly': 0, 'often': 0, 'tremendously': 1, 'totally': 2, 'sharply': 1}

我该如何解决这个问题？

标签： python

解决方案

下面的代码将计算给定文件中的每个单词。

import os

def to_dict(file_path, delimiter=" "):
    dict_list = []  # Each index is a line
    if os.path.exists(file_path):
        with open(file_path, 'rb') as in_file:
            for line in in_file.readlines():  # Grab each line as a list
                line = line.split(delimiter)  # Split at our delim
                new_dict = {}
                for word in line:  # Code to count each index
                    word = word.rstrip()  # Remove formatting
                    if word in new_dict:
                        new_dict[word] += 1
                    else:
                        new_dict[word] = 1
                dict_list.append(new_dict)
        return dict_list
    else:
        print("{} Does not exist. Check the path and try again".format(file_path))

dict_count = to_dict(the_file_path, " ")
if dict_count:  # We found and converted file to a dict
    # function to query against words

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