java - 按下屏幕上的任意位置具有按下按钮的效果

问题描述

我的应用程序有一个按钮，按下时会在 textView 中显示一个新单词，并在 editText 中显示一个新提示。尽管当用户点击屏幕上的任意位置时，它与按钮的效果相同，这显然会导致用户误点击并破坏体验。任何人都可以推荐任何东西。这是按钮的java：

public void nextWord(View view) { //nextWord is the onclick of the button


        Button nextButton = findViewById(R.id.nextButton);
        Button showTextButton = findViewById(R.id.showTextButton);
        TextView wordTextView = findViewById(R.id.wordTextView);
        EditText editTextView = findViewById(R.id.enterEditText);
        ImageView logoImageView = findViewById(R.id.logoImageView);
        TextView wordTextView1 = findViewById(R.id.wordTextView1);


                i++;



        String displayHint;
        String displayText;

        displayText = enterWord() + chooseArray();
        displayHint = chooseArray();

        wordTextView.setText(displayText);
        editTextView.setHint(displayHint);
        wordTextView1.setText(displayText) ;

        if (i == 1) {

            wordTextView.setVisibility(View.VISIBLE);
            editTextView.setVisibility(View.VISIBLE);
            logoImageView.setVisibility(View.INVISIBLE);
            wordTextView1.setVisibility(View.VISIBLE);


            //     wordTextView.setText(enterWord() + initial(0));
            //   editTextView.setHint(initial(0));


        }

if (choice == 5 && i ==1) {
    pickImageButton.setVisibility(View.VISIBLE);
    nextButton.setVisibility(View.INVISIBLE);
    editTextView.setVisibility(View.INVISIBLE);
}else{
    nextButton.setVisibility(View.VISIBLE);
    editTextView.setVisibility(View.VISIBLE);
    pickImageButton.setVisibility(View.INVISIBLE);
}

        if (i == arrayLen()) {
            showTextButton.setVisibility(View.VISIBLE);
            editTextView.setVisibility(View.INVISIBLE);
            wordTextView.setVisibility(View.INVISIBLE);
            nextButton.setVisibility(View.INVISIBLE);
            wordTextView1.setVisibility(View.INVISIBLE);


        }

        enteredWords[i] = editTextView.getText().toString();



    }

这是按钮的 XML：

<Button
        android:id="@+id/nextButton"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_marginTop="180dp"
        android:onClick="nextWord"
        android:text="Next"
        android:visibility="invisible"
        app:layout_constraintBottom_toBottomOf="parent"
        app:layout_constraintEnd_toEndOf="parent"
        app:layout_constraintHorizontal_bias="0.498"
        app:layout_constraintStart_toStartOf="parent"
        app:layout_constraintTop_toTopOf="@+id/enterEditText"
        app:layout_constraintVertical_bias="0.0" />

标签： javaandroidxmlandroid-studiobutton

java - 按下屏幕上的任意位置具有按下按钮的效果

问题描述

解决方案

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