首页 > 解决方案 > 将python中的屏幕截图作为cronjob

问题描述

我需要截屏(windows和linux),但我的代码是从cron/schedulle windows开始的

这是我的代码:

import pyscreenshot as ImageGrab
if __name__ == "__main__":

    # grab fullscreen
    im = ImageGrab.grab()

    # save image file
    im.save("screenshot.png")

    # show image in a window
    im.show()

这给我返回了以下错误:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/__init__.py", line 43, in grab
    return _grab(childprocess=childprocess, backend=backend, bbox=bbox)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/__init__.py", line 29, in _grab
    return childprocess_grab(_grab_simple, backend, bbox)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/childproc.py", line 34, in childprocess_grab
    return childprocess_grab_popen(backend, bbox)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/childproc.py", line 54, in childprocess_grab_popen
    raise FailedBackendError(p)
pyscreenshot.loader.FailedBackendError: <EasyProcess cmd_param=['/usr/bin/python3', '-m', 'pyscreenshot.cli.grab_to_file', '/tmp/pyscreenshot0lficj00/screenshot.png', '0', '0', '0', '0', '--backend', ''] cmd=['/usr/bin/python3', '-m', 'pyscreenshot.cli.grab_to_file', '/tmp/pyscreenshot0lficj00/screenshot.png', '0', '0', '0', '0', '--backend', ''] oserror=None return_code=1 stdout="" stderr="Traceback (most recent call last):
  File "/usr/lib/python3.7/runpy.py", line 193, in _run_module_as_main
    "__main__", mod_spec)
  File "/usr/lib/python3.7/runpy.py", line 85, in _run_code
    exec(code, run_globals)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/cli/grab_to_file.py", line 8, in <module>
    def main(filename, x1, y1, x2, y2, backend=""):
  File "/usr/local/lib/python3.7/dist-packages/entrypoint2/__init__.py", line 440, in entrypoint
    return func(**kwargs)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/cli/grab_to_file.py", line 28, in main
    im = pyscreenshot.grab(bbox=bbox, childprocess=False, backend=backend)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/__init__.py", line 43, in grab
    return _grab(childprocess=childprocess, backend=backend, bbox=bbox)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/__init__.py", line 31, in _grab
    return _grab_simple(backend, bbox, filename)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/__init__.py", line 17, in _grab_simple
    return backend_obj.grab(bbox)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/plugins/scrot.py", line 24, in grab
    im = read_prog_img([PROGRAM, "--silent"])
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/tempexport.py", line 28, in read_prog_img
    im = read_func_img(run_prog)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/tempexport.py", line 16, in read_func_img
    func(filename, bbox)
  File "/usr/local/lib/python3.7/dist-packages/pyscreenshot/tempexport.py", line 26, in run_prog
    raise RunProgError(p.stderr)
pyscreenshot.tempexport.RunProgError: giblib error: Can't open X display. It *is* running, yeah?" timeout_happened=False>

我需要帮助来解决它。我试图改变 lib 但我发现没有一个工作。


我注意到,如果我与用户一起在 crontab 或 ssh 中运行,我的代码会运行,但在 root 中则不会。(我需要用 sudo 执行它来进行一些系统调整、文件移动和读取日志)

标签: python-3.xscreenshot

解决方案


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