python - 使用 Python 从文本文件中提取 StatusDescription

Question

我有一个示例文本文件。我想为每一行提取 StatusDescription 并且如果它不可用，我希望它返回一个 null 即

第 1 行状态描述=空

Line2 StatusDescription=成功

示例文本文件：

[2019 年 10 月 23 日] [12:14:49:150] [[ACTIVE] ExecuteThread: '7' for queue: 'weblogic.kernel.Default (self-tuning)'] [22368936] [172.30.26.90] [ c84283f4-5a3d-4559-b8d1-6ae2bdfc6075][com.intellectdesign.iportal.as.integrator.host.GenericCommunicator][EXIT] {离开 sendToHostEx 方法...}

[2019 年 10 月 23 日] [12:14:49:150] [[ACTIVE] ExecuteThread: '7' for queue: 'weblogic.kernel.Default (self-tuning)'] [22368936] [172.30.26.90] [ c84283f4-5a3d-4559-b8d1-6ae2bdfc6075][com.intellectdesign.digitalface.formatter.CoopCardSummmaryFormatter][错误] {hdr_Tran_Id=COOP_CARD_DETAILS~*hdr_Ref_No=1~*res_Status=00000~*CorrelationID=AAAAAD7B5619~*IDMessage StatusCode=S_001~*StatusDescription=成功~*StatusDescriptionKey=en-US}

标签： pythonnlplog-analysis

Answer 1

这应该适用于您的情况：

import re

def find_substring(line):
    try:
        result = re.search('StatusDescription=(.*)~', line)
        return result.group(1)
    except:
        return "Null"

with open('text.txt') as f:
    lines = f.readlines()
    for line in lines:
        status_description = find_substring(line)
        print(status_description)