python - Python tkinter 将值传递给另一个类（似乎只接受一个值）

Question

我正在尝试制作一个 tkinter GUI，它将抓取网站的某些部分，以使其对用户友好，我制作它以便它在 tkinter 中具有不同的框架。问题是，在帧之间切换时，我似乎无法传递其他信息。这是我的代码（https://codeshare.io/aYXv6Y）：

import tkinter as tk                # python 3
from tkinter import font  as tkfont # python 3
from bs4 import BeautifulSoup
import requests
import time


class SampleApp(tk.Tk):

    def __init__(self, *args, **kwargs):
        tk.Tk.__init__(self, *args, **kwargs)

        self.geometry("650x350")
        self.title_font = tkfont.Font(family='Helvetica', size=18, weight="bold", slant="italic")
        self.title_font2 = tkfont.Font(family='Calibri', size=11)
        self.title_fontmainTMenu = tkfont.Font(family='Helvetica', size=16)
        self.title_fontDevices = tkfont.Font(family='Didot', size=13)
        self.title_fontT = tkfont.Font(family='Cambria', size=16)
        self.title("League of Legends Helper")
        changeChampX = 525
        changeChampY = 310

        # the container is where we'll stack a bunch of frames
        # on top of each other, then the one we want visible
        # will be raised above the others
        container = tk.Frame(self)
        container.pack(side="top", fill="both", expand=True)
        container.grid_rowconfigure(0, weight=1)
        container.grid_columnconfigure(0, weight=1)

        self.frames = {}
        for F in (MainMenu, ChampionSelect, ChampionRunes):
            page_name = F.__name__
            frame = F(parent=container, controller=self)
            self.frames[page_name] = frame

            # put all of the pages in the same location;
            # the one on the top of the stacking order
            # will be the one that is visible.
            frame.grid(row=0, column=0, sticky="nsew")

        self.show_frame("MainMenu")

    def show_frame(self, page_name):
        '''Show a frame for the given page name'''
        frame = self.frames[page_name]
        frame.tkraise()

    def setChampion(self, championName, championRole):
        self.championName = championName
        self.championRole = championRole


class MainMenu(tk.Frame):

    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        self.controller = controller
        label = tk.Label(self, text="Welcome to the Main Menu", font=controller.title_font)
        label.pack(side="top", fill="x", pady=10)

        button1 = tk.Button(self, text="Go to Champion Select",
                            command=lambda: controller.show_frame("ChampionSelect"))
        button1.pack()


class ChampionSelect(tk.Frame):

    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        self.controller = controller
        label = tk.Label(self, text="Which Champion are you playing?", font=controller.title_fontmainTMenu)
        label.place(x=170, y=70)

        nameOfChampionE = tk.Entry(self)
        nameOfChampionE.place(x=170, y=150, width=120, height = 20)

        roleOfChampionE = tk.Entry(self)
        roleOfChampionE.place(x=170, y=250, width=120, height=20)

        page = requests.get('https://champion.gg/champion/Katarina/Middle?')
        soup = BeautifulSoup(page.text, 'lxml')

        championData = soup.find('div', 'summoner-text')




        def whichChampion():
            championName = nameOfChampionE.get()
            championRole = roleOfChampionE.get()
            controller.setChampion(championName, championRole)
            command = controller.show_frame("ChampionRunes")

        submitName = tk.Button(self, text="Show Champion details",
                               command=lambda: whichChampion())
        submitName.place(x=170, y=185)




class ChampionRunes(tk.Frame):

    def __init__(self, parent, controller):
        tk.Frame.__init__(self, parent)
        self.controller = controller
        label = tk.Label(self, text="", font=controller.title_font)
        label.pack(side="top", fill="x", pady=10)



        button = tk.Button(self, text="Change Champion",
                           command=lambda: controller.show_frame("ChampionSelect"))
        button.place(x=525, y=310)

        # URL = f"https://champion.gg/champion/{controller.championName.capitalize()}/{controller.championRole.capitalize()}?"


        text = controller.ChampionName
        titleChamp = tk.Label(self, text=f"{text}", font=controller.title_fontmainTMenu)
        titleChamp.place(x=170, y=70)







if __name__ == "__main__":
    app = SampleApp()
    app.mainloop()

尝试传递 ChampionName 和 ChampionRole 时，出现错误：

Traceback (most recent call last):
  File "(FILE PATH)", line 130, in <module>
    app = SampleApp()
  File "(FILE PATH)", line 34, in __init__
    frame = F(parent=container, controller=self)
  File "(FILE PATH)", line 119, in __init__
    text = controller.ChampionName
  File "(FILE PATH)", line 2345, in __getattr__
    return getattr(self.tk, attr)
AttributeError: '_tkinter.tkapp' object has no attribute 'ChampionName'

ChampionName 和 ChampionRole 是我正在解析的网站的 URL 的一部分的关键信息，所以我真的不知道该怎么做。我对代码的某些部分不熟悉，并且对 python 和 tkinter 还是新手，所以请尽量清楚。

任何帮助将非常感激。谢谢！

标签： pythonpython-3.xtkinter