首页 > 解决方案 > 如何使范围部分属性“特定用途”值 - XSLT

问题描述

我正在尝试对specific-use单个 para 元素中的范围部分属性进行编号。我正在获取单个值<span style="case">group-by获取值group-by="ancestor::sec[1]"。当<span style="case">值继续时是否可以使范围继续descendant::,或者following-sibling::我们可以获取最后一个specific-use值。
输入 XML

<book>
<sec disp-level="1" specific-use="1">
    <p>aaaaaa</p>
    <sec disp-level="2" specific-use="2">
        <p><span style="case">super</span></p>
    </sec>
    <sec disp-level="2" specific-use="3">
        <blockquote>
        <p><span style="case">super</span></p>
        </blockquote>
    </sec>
    <sec disp-level="2" specific-use="4">
            <p><span style="case">super</span></p>
    </sec>
</sec>
<sec disp-level="1" specific-use="5">
    <p><span style="case">super</span>, <span style="case">active</span></p>
    <sec disp-level="2" specific-use="6">
        <p><span style="case">active</span></p>
    </sec>
</sec>
<sec disp-level="1" specific-use="7">
    <p><span style="case">active</span></p>
    <sec disp-level="2" specific-use="8">
        <p><span style="case">active</span></p>
    </sec>
    <sec disp-level="2" specific-use="9">
        <p><span style="case">super</span></p>
    </sec>
    <sec disp-level="2" specific-use="10">
        <p><span style="case">active</span></p>
    </sec>
</sec>

XSLT 代码

      <xsl:template match="book">
    <xsl:copy>
        <xsl:for-each-group select="//*" group-by="span[@style='case']">
            <xsl:text>&#x0A;</xsl:text>
            <p>
                <case><xsl:value-of select="current-grouping-key()"/></case><xsl:text> </xsl:text>
            <sec>
              <xsl:for-each select="current-group()">
                <number>
                    <xsl:value-of select="ancestor::sec[1]/@specific-use"/>
                </number>
                  <xsl:if test="position()!=last()">
                      <xsl:text>, </xsl:text>
                  </xsl:if>
              </xsl:for-each>
            </sec>
            </p>
        </xsl:for-each-group>
    </xsl:copy>
</xsl:template>

我的 XSLT 给定输出 https://xsltfiddle.liberty-development.net/3NSTbfj/7
我的预期输出

<book>
<p><case>super</case> <sec><number>2</number>&#x2013;<number>4</number>, <number>5</number>, <number>9</number></sec></p>
<p><case>active</case> <sec><number>5</number>&#x2013;<number>8</number>, <number>10</number></sec></p>
</book>

例如:

超级 2–4, 5, 9

活跃 5–8, 10


2–4:创建范围因为<span style="case">super</span>搜索继续相同的值child::following-sibling::
5–8:创建范围因为<span style="case">active</span>搜索继续相同的值child::following-sibling::

标签: xsltxslt-2.0xslt-3.0

解决方案


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