时间戳

首页 > 解决方案 > 将 GameObjects 分配给列表并给它们一个索引

c# - 将 GameObjects 分配给列表并给它们一个索引

问题描述

所以基本上，我有一个每个数字有 2 个的列表，我想将其中一个数字随机分配给每张实例化的卡片。这是一个益智记忆游戏，您可以在其中找到匹配项。

当我有 2 个 gridRows 和 4 个 gridCols 时，游戏运行良好，但如果我更改行数或列数，我会得到：ArgumentOutOfRangeException：索引超出范围。必须是非负数且小于集合的大小。参数名：index，阻止我扩展游戏。我尝试在当前列表中添加其他数字，但这似乎不起作用，而且如果我想要有很多行和列，这种方式似乎也不是很有效

我想要做的是获取一个列表，然后在每次开始比赛时对其内容进行洗牌，然后在我实例化时按顺序循环索引（内容已经洗牌），这是我的逻辑，但无法让它工作一些原因....

有人可以帮我扩展它并找到存储索引的更好方法吗？

这是代码：

 public const int gridRows = 2;
public const int gridCols = 4;
public const float offsetX = 4f;
public const float offsetY = 5f;

public MainCard originalCard;
public Sprite[] images;


private void Start()
{
    Vector3 startPos = originalCard.transform.position;
    List<int> numbers = new List<int> { 0, 0, 1, 1, 2, 2, 3, 3 };
    numbers = Shuffle(numbers);

    for (int i = 0; i < gridCols; i++)
    {
        for (int x = 0; x < gridRows; x++)
        {
            MainCard card;
            if (i == 0 && x == 0)
            {
                card = originalCard;
            }
            else
            {
                card = Instantiate(originalCard) as MainCard;
            }

            int index = x * gridCols + i;
            int id = numbers[index];
            card.ChangeSprite(id, images[id]);

            float posX = (offsetX * i) + startPos.x;
            float posY = (offsetX * x) + startPos.y;
            card.transform.position = new Vector3(posX, posY, startPos.z);
        }
    }

    List<T> Shuffle<T>(List<T> cards)
    {
        for (int i = 0; i < cards.Count; i++)
        {
            T temp = cards[i];
            int randomIndex = Random.Range(i, cards.Count);
            cards[i] = cards[randomIndex];
            cards[randomIndex] = temp;
        }

        return cards;
    }

}

}

标签： c#oopunity3d

解决方案

一种解决方案是将您的项目分成更多部分：

using System.Linq;//to Add

public int gridRows = 2;
public  int gridCols = 4;
public List<int> numbers;
public void Start()
{
    int[,] cards = new int[gridRows, gridCols];
    //just put different numbers not needed to duplicate 
    //except if you want to increase the probability
    // to have lot of same number
    numbers = new List<int> { 0, 1, 2, 3 };
    InitializeGame(cards);
}

private void InitializeGame(int[,] cards)
{
    //1 you could shuffle your number if you want
    //numbers = Shuffle(numbers);

    //2 you initialize cards to value not used (-1 here)
    for (int r = 0; r < gridRows; r++)
    {
        for (int c = 0; c < gridCols; c++)
        {
            cards[r, c] = -1;
        }
    }

    // Test if you have filled up all cards
    //Is there again one card with the value -1?
    while (cards.Cast<int>().Any(x => x == -1))
    {
        //3 you pick randomnly a number
        var numCard = numbers[Random.Range(0, numbers.Count)];

        //4 you fill same number to 2 different cards here
        var nbcardTofill = 2;
        while (nbcardTofill != 0)
        {
            //you choose randomny card (row and col) which is free (value = -1) not need but add fun
            var colRandom = Random.Range(0, gridCols);
            var rowRandom = Random.Range(0, gridRows);
            if(cards[rowRandom, colRandom] == -1)
            {
                nbcardTofill--;
                cards[rowRandom, colRandom] = numCard;
            }
        }
    }
}

现在你有了填满数字的阵列卡，你现在可以抽奖了..

因此您可以根据需要更改列数/行数和数字列表...

只是一种编程方式，但我认为它更具可读性。我添加了很多随机化来增加乐趣......

另一种方法是按顺序填写您的卡片（2 x 2 相同的数字）并在最后对所有卡片进行洗牌......

推荐阅读