sql - 执行列名错误的查询时没有错误
问题描述
我遇到了奇怪的行为,至少在 SQL Server 上(我仍然需要检查其他 SQL 引擎),同时尝试删除一些记录。
我在 SQL Server 实例上测试了以下内容:
- Microsoft SQL Server 2019 (RTM) - 15.0.2000.5 (X64) Sep 24 2019 13:48:23 版权所有 (C) 2019 Microsoft Corporation Developer Edition (64-bit) on Windows 10 Enterprise 2016 LTSB 10.0 (Build 14393: )
- Microsoft SQL Server 2016 (SP1) (KB3182545) - 13.0.4001.0 (X64) Oct 28 2016 18:17:30 版权所有 (c) Microsoft Corporation Standard Edition (64-bit) on Windows Server 2012 R2 Standard 6.3 (Build 9600:) (管理程序)
这是一个 SQL 代码片段。这是我试图做的事情的简化版本,肯定可以讨论为什么要以这种方式进行查询,但我的观点不同——为什么会发生这种情况。
drop table if exists #A
drop table if exists #B
create table #B (id char, foo char) -- I use different types for id columns just for the sake of readability
create table #A (id int, b_id char) -- b_id is a link to #A, _not_ specified as FK
insert into #B values('x', 'l')
insert into #B values('y', 'm')
insert into #A values(0, 'x')
insert into #A values(1, 'z')
insert into #A values(2, 'z')
insert into #A values(3, 'y')
insert into #A values(4, 'y')
insert into #A values(5, 'y')
-- there are 2 parent records in #B and 3 child records for each of them in #A
select * from #A -- just to check, all good the data is there, all as expected, no problem
-- now the fun part
--(X) the following query, rightfully gives an error, as column b_id does not exist in #B
-- select b_id from #B where foo='l'
--(Y) the following query gives empty result, whereas I would expect an error:
select * from #A where b_id in (select b_id from #B where foo='l')
-- I can imagine that this has something to do with the fact that b_id exists in table #A in outer query
--(Z) the following query deletes(!) all data in table #A:
delete from #A where b_id in (select b_id from #B where foo='l')
select * from #A
-- once again, I can imagine that there is no error message "Invalid column name 'b_id'." because b_id exists in table #A in outer query
所以这是我的问题:
- 为什么查询 (Y) 和 (Z) 中没有关于无效列的错误消息?我会对细节感兴趣
- 根据答案(1),知道为什么查询(Y)提供空结果会很有趣。明明如果inner select为空,则outer应该为空,但魔鬼隐藏在细节中
- 为什么查询 (Z) 会删除表 #A 中的所有记录?我希望受影响的记录(在 (Y) 的情况下返回并在 (Z) 的情况下删除)应该是相同的
解决方案
问题 1(Y):
(实时和实际)执行计划表明您的想象是正确的:显示了每个节点的输出,包括表前缀 - 不会混淆:节点 3 返回以下两列:[#A].[id], [#A].[b_id]
,而节点 4 没有什么可返回但NULL
/*
id b_id
----------- ----
0 x
1 z
2 z
3 y
4 y
5 y
(6 rows affected)
Table '#B__________________________________________________________________________________________________________________000000000335'. Scan count 1, logical reads 6, physical reads 0, page server reads 0, read-ahead reads 0, page server read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob page server reads 0, lob read-ahead reads 0, lob page server read-ahead reads 0.
Table '#A__________________________________________________________________________________________________________________000000000336'. Scan count 1, logical reads 1, physical reads 0, page server reads 0, read-ahead reads 0, page server read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob page server reads 0, lob read-ahead reads 0, lob page server read-ahead reads 0.
Rows Executes StmtText NodeId Parent PhysicalOp LogicalOp Argument DefinedValues EstimateRows EstimateIO EstimateCPU AvgRowSize TotalSubtreeCost OutputList Warnings Type EstimateExecutions
---- -------- ------------------------------------------------------------------------------------ ------ ------ ------------ -------------- -------------------------------------------------------------- ----------------------- ------------- ------------- ------------- ----------- ---------------- ----------------------- -------- --------- ------------------
6 1 select * from #A where b_id in (select b_id from #B where foo='l') 1 0 NULL NULL NULL NULL 6 NULL NULL NULL 0,00701002 NULL NULL SELECT NULL
6 1 |--Nested Loops(Left Semi Join) 2 1 Nested Loops Left Semi Join NULL NULL 6 0 2,508E-05 12 0,00701002 [#A].[id], [#A].[b_id] NULL PLAN_ROW 1
6 1 |--Table Scan(OBJECT:([tempdb].[dbo].[#A]), WHERE:([#A].[b_id]=[#A].[b_id])) 3 2 Table Scan Table Scan OBJECT:([tempdb].[dbo].[#A]), WHERE:([#A].[b_id]=[#A].[b_id]) [#A].[id], [#A].[b_id] 6 0,003125 0,0001636 12 0,0032886 [#A].[id], [#A].[b_id] NULL PLAN_ROW 1
6 6 |--Table Scan(OBJECT:([tempdb].[dbo].[#B]), WHERE:([#B].[foo]='l')) 4 2 Table Scan Table Scan OBJECT:([tempdb].[dbo].[#B]), WHERE:([#B].[foo]='l') NULL 1 0,0032035 8,07E-05 9 0,0036877 NULL NULL PLAN_ROW 6
(4 rows affected)
*/
问题 2:查询确实返回结果。
问题 3:
SELECT * FROM #A WHERE b_id IN (SELECT b_id FROM #B WHERE foo = 'l');
SELECT * FROM #A WHERE EXISTS (SELECT 'YAAAY' FROM #B WHERE foo = 'l');
SELECT * FROM #A WHERE EXISTS (SELECT 'YAAAY' FROM #B WHERE foo = 'asdafadsf');
我认为 OP 的查询可以重写为等效的 EXISTS 查询。
将b_id
始终等于b_id
,除非该IN ()
部件没有返回任何结果。
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