javascript - 如何使用而不是触发模态

Question

单击按钮时，我使用此（w3school）代码触发模式

// Get the modal
var modal = document.getElementById("myModal");

// Get the button that opens the modal
var btn = document.getElementById("myBtn");

// Get the <span> element that closes the modal
var span = document.getElementsByClassName("close")[0];

// When the user clicks on the button, open the modal
btn.onclick = function() {
  modal.style.display = "block";
}

// When the user clicks on <span> (x), close the modal
span.onclick = function() {
  modal.style.display = "none";
}

// When the user clicks anywhere outside of the modal, close it
window.onclick = function(event) {
  if (event.target == modal) {
    modal.style.display = "none";
  }
}

而不是使用按钮，我想使用<a>'sonclick=function()方法来触发模态。我已经尝试交换*tn.onlclick-part，但这没有用。如何做到这一点？

标签： javascripthtmlcss

Answer 1

您可以将a标签与preventDefault

const opener = document.querySelector('.btn');

opener.onclick = function(e) {
  e.preventDefault(); // to prevent link's default behaviour
  modal.style.display = "block";
}

<a class="btn" href="#">Open</a>