java - 在文字冒险游戏中移动

问题描述

我正在做一个简单的文本冒险项目。当我运行代码时，当我尝试输入右/左/向前/向后两次时，它将不起作用。它重置到游戏的开始。

此外，当我输入任何不符合这些 if 语句顺序的输入时，例如向前然后向左，程序会进入我的故障安全状态。我之前问过这个问题，有人回答说我应该在我的代码中使用 if else。我可以为这个项目使用哪些其他替代方案？

故障保险也不起作用。我按批准的方向键入，但故障保护无限期地继续。

Scanner key = new Scanner(System.in);
int x, y;
x = 0;
y = 0;
String gameStart = "c";
String direction = "c";

System.out.print("Welcome to my text adventure game!\nIf you want to play, type in 'Start'");
gameStart = key.next();

while(!"Start".equals(gameStart))
{
  System.out.print("Incorrect input.  Type in 'Start' to begin:  ");
  gameStart = key.next();
}

while(gameStart.equals("Start"))
{
  direction = "";
  x = 0;
  y = 0;
  System.out.println("");
  System.out.print("You wake up in an extremly small room.  You estimate it to be a perfectly sized 3x3 room.  Based on your estimation, your in the center of the room.  Dispite that there is a bed directly behind you, you wake up on a circular rug.  Weird, but, the door's right in front of you.  Time to escape!\nYou can move forward, backwards, left and right.");
  direction = key.next();

  if(direction.equals("right") || direction.equals("Right"))
  {
    x++;
    System.out.print("You walk to the right.");
    direction = key.next();
  }

  else if (direction.equals("left") || direction.equals("Left"))
  {
    x--;
    System.out.print("You walk to the left.");
    direction = key.next();
  }

  else if (direction.equals("forward") || direction.equals("Forward"))
  {
    y++;
    System.out.print("You walk Forward.");
    direction = key.next();
  }

  else if (direction.equals("backwards") || direction.equals("Backwards"))
  {
    y--;
    System.out.print("You walk backwards.");
    direction = key.next();
  }
  else 
  {
    do
    {
    System.out.print("Sorry, you can't do that.  Try again:");
    direction = key.next();
    }
    while(!direction.equals("right")|| !direction.equals("Right") || !direction.equals("left") || !direction.equals("Left") || !direction.equals("forward") || !direction.equals("Forward") || !direction.equals("backwards") || !direction.equals("Backwards"));
  }

while(gameStart.equals("Start"))
  {
    if (x<-2 || x>2 || y<-2 || y>2)
    {
      System.out.println("ERROR:  OUT OF BOUNDS");
      System.exit(0);
    }
    if (x==-2 || x==2)
    {
      System.out.println("You try to walk further, however, you run right into a wall.");
      x--;
    }
    if (y==-3 || y==3)
    {
      System.out.println("You try to walk further, however, you run right into a wall.");
      y--;
    }
  }
}

标签： javajava.util.scanner

在你的 while 循环后面有一个分号，这使它立即结束。

while(gameStart.equals("Start"));

此外，这段代码中有很多不好的做法，比如：

与文字字符串而不是常量进行比较
将变量初始化为某个随机值，只需将它们保留为空值
将你的 gameStart 逻辑存储为一个字符串，当它是一个布尔值更有意义时
当您可以使用 .ToLower() 或大小写激励 Equals() 时，您有两个相等检查

还有很多要批评的东西，但我想你才刚刚开始:)

java - 在文字冒险游戏中移动

问题描述

解决方案

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