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python - 如何在 Python 中忽略“KeyError”

问题描述

我正在尝试使用 api“yfinance”分析 python 中的股票。我让程序在大多数情况下都能正常运行。但是，当它无法“找到”其中一个字段时，它会出现错误（KeyError）。这是我的代码片段。

import yfinance as yf
stock = yf.Ticker(stock)
pegRatio = stock.info['pegRatio']
print(pegRatio)
if pegRatio > 1:
    print("The PEG Ratio for "+name+" is high, indicating that it may be overvalued (based on projected earnings growth).")
if pegRatio == 1:
    print("The PEG Ratio for "+name+" is 1, indicating that it is close to fair value.")
if pegRatio < 1:
    print("The PEG Ratio for "+name+" is low, indicating that it may be undervalued (based on projected earnings growth).")

这是错误 Traceback（最近一次调用最后一次）：第 29 行，industry = stock.info['industry'] KeyError: 'industry'

我的主要问题是如何让代码基本上忽略错误并运行其余代码？

标签： pythonerror-handlingkeyerror

解决方案

Python 中的错误处理

就像Nicolas已经评论过的那样，您会在网络上找到许多教程、博客文章和视频。还有一些涵盖“错误处理”的基本 Python 书籍。

Python 中的控制结构至少包含 2 个关键字try和except，通常命名为try-except block。还有 2 个可选关键字else和finally.

如何包装你的失败陈述

import yfinance as yf

try: # st art watching for errors
  stock = yf.Ticker(stock)  # the API call may also fail, e.g. no connection
  pegRatio = stock.info['pegRatio']  # here your actual exception was thrown
except KeyError:  # catch unspecific or specific errors/exceptions
  # handling this error type begins here: print and return
  print "Error: Could not find PEG Ratio in Yahoo! Finance response!"
  return 

# the happy path continues here: with pegRatio
print(pegRatio)
if pegRatio > 1:
    print("The PEG Ratio for "+name+" is high, indicating that it may be overvalued (based on projected earnings growth).")
if pegRatio == 1:
    print("The PEG Ratio for "+name+" is 1, indicating that it is close to fair value.")
if pegRatio < 1:
    print("The PEG Ratio for "+name+" is low, indicating that it may be undervalued (based on projected earnings growth).")

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