首页 > 解决方案 > 将 json 对象作为键控消息传递给 apache kafka

问题描述

我有一个 json 对象,它具有不同的订单状态。我想把它推到 apache kafka。顺序至关重要,因为我设置了消费数据的消费者。我计划使用订单 ID 作为消息的键,因为它将按顺序存储在同一个分区中。

data = [{"id": 1, "orderId": "A123","status":"PLACED"},{"id": 2, "orderId": "B123","status":"PLACED"}
{"id": 3, "orderId": "A123","status":"DISPATCHED"}]

from kafka import KafkaProducer
import json
producer = KafkaProducer(bootstrap_servers=os.environ['KAFKA_BROKER_URLS'],security_protocol="SSL")
for item in data:
    d = json.dumps(item)
    future = producer.send(topic,key=item['orderId'], value=d)

但是我在生产者中收到了 assertionError 。我什至试过

d = json.dumps(item).encode('utf-8')
future = producer.send(topic,key=item['orderId'], value=d)

也可以通过在初始化代码中定义值序列化器,例如

producer = KafkaProducer(bootstrap_servers=os.environ['KAFKA_BROKER_URLS'],security_protocol="SSL",value_serializer=lambda v: json.dumps(v).encode('utf-8'))

他们都给出了同样的错误。如果我删除密钥并传递数据

d = json.dumps(item).encode('utf-8')    
future = producer.send(topic,d)

这是有效的,消息被推送到 kafka 并显示在消费者端。但是我想传递密钥,以保持相同订单ID的顺序。我该如何解决?

更新 1:

这是错误:

{
  "errorType": "AssertionError",
  "stackTrace": [
    "  File \"/var/task/producer.py\", line 56, future = producer.send(topic,key=item['orderId'], value=d)\n",
    "  File \"/opt/python/lib/python3.7/site-packages/kafka/producer/kafka.py\", line 572, in send\n    assert type(key_bytes) in (bytes, bytearray, memoryview, type(None))\n"
  ]
}

标签: python-3.xapache-kafkakafka-producer-apikafka-python

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