首页 > 解决方案 > 计算行列式。从主对角线 X 的每个元素中减去

问题描述

我的程序计算矩阵的行列式。

方阵大小 = 3 源矩阵

1 2 3 4 5 6 -> и вычесть из каждого элемента главной диагонали X 7 8 9

1-x 2 3 4 5-x 6 ->решить определитель 7 8 9-x

     #include<iostream>
     #include<math.h>
   using namespace std;
   int determinant(int matrix[10][10], int n) {

    int det = 0;
     int submatrix[10][10];
 if (n == 2)
      return ((matrix[0][0] * matrix[1][1]) - (matrix[1][0] * matrix[0][1]));
  else {
    for (int x = 0; x < n; x++) {
        int subi = 0;
        for (int i = 1; i < n; i++) {
            int subj = 0;
            for (int j = 0; j < n; j++) {
                if (j == x)
                    continue;
                submatrix[subi][subj] = matrix[i][j];
                subj++;
            }
            subi++;
        }
        det = det + (pow(-1, x) * matrix[0][x] * determinant(submatrix, n - 1));
    }
}
return det;
}
int main() {
int n, i, j,x;
int matrix[10][10];
cout << "Enter the size of the matrix:\n";
cin >> n;
cout << "Enter the elements of the matrix:\n";
for (i = 0; i < n; i++)
    for (j = 0; j < n; j++)
        cin >> matrix[i][j];
cout << "The entered matrix is:" << endl;
for (i = 0; i < n; i++) {
    for (j = 0; j < n; j++)
        cout << matrix[i][j] << " ";
    cout << endl;

}
cout << "Determinant of the matrix is " << determinant(matrix, n);
return 0;
     }

标签: c++stringmatrixdeterminantsmassive

解决方案


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