首页 > 解决方案 > 等待 useLazyQuery 响应

问题描述

我需要在按下提交按钮时调用查询,然后处理响应。

我需要这样的东西:

const [checkEmail] = useLazyQuery(CHECK_EMAIL)
const handleSubmit = async () => {
  const res = await checkEmail({ variables: { email: values.email }})
  console.log(res) // handle response
}

尝试#1:

const [checkEmail, { data }] = useLazyQuery(CHECK_EMAIL)
const handleSubmit = async () => {
  const res = await checkEmail({ variables: { email: values.email }})
  console.log(data) // undefined the first time
}

提前致谢!

标签: reactjsgraphqlapollo-client

解决方案


这对我有用:

const { refetch } = useQuery(CHECK_EMAIL, {
  skip: !values.email
})

const handleSubmit = async () => {
  const res = await refetch({ variables: { email: values.email }})
  console.log(res)
}

推荐阅读