r - 划分两个矩阵列表，其中一个列表中的第 i 个矩阵元素除以第二个列表中的第 i 个矩阵元素

Question

我有两个矩阵列表。以下是它们的结构示例：

list1<- list(structure(c(1, 2, 7, 1, 3, 0, 0, 0, 1, 4, 1, 3, 2, 3, 4, 
6, 0, 0, 0, 3, 3), .Dim = c(7L, 3L), .Dimnames = list(c("lepA", 
"lepB", "lepC", "lepD", "lepE", "lepF", "lepG"), NULL)), structure(c(1, 
3, 7, 1, 3, 2, 3, 4, 6, 4, 1, 3, 3, 3), .Dim = c(7L, 2L), .Dimnames = list(
c("lepA", "lepB", "lepC", "lepD", "lepE", "lepF", "lepG"), 
NULL)), structure(c(5, 8, 7, 1, 3, 3, 3), .Dim = c(7L, 1L
), .Dimnames = list(c("lepA", "lepB", "lepC", "lepD", "lepE", 
"lepF", "lepG"), NULL)))

list2<-list(structure(c(6, 1, 51, 13, 15, 0, 0, 0, 6, 50, 13, 15, 6, 
5, 5, 9, 0, 0, 0, 7, 5), .Dim = c(7L, 3L), .Dimnames = list(c("lepA", 
"lepB", "lepC", "lepD", "lepE", "lepF", "lepG"), NULL)), structure(c(6, 
7, 51, 13, 15, 6, 5, 5, 9, 50, 13, 15, 7, 5), .Dim = c(7L, 2L
), .Dimnames = list(c("lepA", "lepB", "lepC", "lepD", "lepE", 
"lepF", "lepG"), NULL)), structure(c(11, 10, 51, 13, 15, 7, 5
), .Dim = c(7L, 1L), .Dimnames = list(c("lepA", "lepB", "lepC", 
"lepD", "lepE", "lepF", "lepG"), NULL)))

我需要将列表中每个矩阵的每个元素与第二个列表中匹配矩阵中的相应元素相除。就好像两个矩阵列表应该是一个数组列表，并且为每个数组元素计算被除数。结果将是：

list<- list(list1[[1]]/list2[[1]], list1[[2]]/list2[[2]], list1[[3]]/list2[[3]])

我试过：

list1/list2 

标签： rarrayslistmatrix

Answer 1

使用Map：

Map(`/`, list1, list2)

#[[1]]
#           [,1]       [,2]      [,3]
#lepA 0.16666667        NaN 0.8000000
#lepB 2.00000000 0.16666667 0.6666667
#lepC 0.13725490 0.08000000       NaN
#lepD 0.07692308 0.07692308       NaN
#lepE 0.20000000 0.20000000       NaN
#lepF        NaN 0.33333333 0.4285714
#lepG        NaN 0.60000000 0.6000000

#[[2]]
#           [,1]       [,2]
#lepA 0.16666667 0.80000000
#lepB 0.42857143 0.66666667
#lepC 0.13725490 0.08000000
#lepD 0.07692308 0.07692308
#lepE 0.20000000 0.20000000
#lepF 0.33333333 0.42857143
#lepG 0.60000000 0.60000000

#[[3]]
#           [,1]
#lepA 0.45454545
#lepB 0.80000000
#lepC 0.13725490
#lepD 0.07692308
#lepE 0.20000000
#lepF 0.42857143
#lepG 0.60000000

或map2在purrr

purrr::map2(list1, list2, `/`)