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javascript - 如何检查对象数组是否所有值都重复？

问题描述

var values = [
    { name: 'Car',Data:'Required',value:'Vehicle' },
    { name: 'Auto',Data:'Required',value:'Vehicle'},
    { name: 'Bike',Data:'Required',value:'Vehicle'},
    { name: 'Car',Data:'Required',value:'Vehicle' }
];

重复的对象将是：{ name: 'Car',Data:'Required',value:'Vehicle' }

标签： javascriptangulartypescript

解决方案

如果要检查对象的所有属性，则必须引入一个新函数，并使用它来过滤数组：

var values = [
    { name: 'Car',Data:'Required',value:'Vehicle' },
    { name: 'Auto',Data:'Required',value:'Vehicle'},
    { name: 'Bike',Data:'Required',value:'Vehicle'},
    { name: 'Bike',Data:'Required',value:'Different VL'},
    { name: 'Car',Data:'Required',value:'Vehicle' }
];

Object.compare = function (obj1, obj2) {
	//Loop through properties in object 1
	for (var p in obj1) {
		//Check property exists on both objects
		if (obj1.hasOwnProperty(p) !== obj2.hasOwnProperty(p)) return false;
 
		switch (typeof (obj1[p])) {
			//Deep compare objects
			case 'object':
				if (!Object.compare(obj1[p], obj2[p])) return false;
				break;
			//Compare function code
			case 'function':
				if (typeof (obj2[p]) == 'undefined' || (p != 'compare' && obj1[p].toString() != obj2[p].toString())) return false;
				break;
			//Compare values
			default:
				if (obj1[p] != obj2[p]) return false;
		}
	}
 
	//Check object 2 for any extra properties
	for (var p in obj2) {
		if (typeof (obj1[p]) == 'undefined') return false;
	}
	return true;
};


var doubles = values.filter((x,i,a) =>a.slice(0,i).find(y=>Object.compare(x,y)))

console.log(doubles)

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