首页 > 解决方案 > 以 pgm 文件格式的输出构建频率表

问题描述

在这里我正在阅读 PGM 格式我想在 C++ 中为霍夫曼压缩和解压缩构建频率表如何提取图片的输出以制作频率表?考虑到我可能会使用此源代码,我是否应该将其转换为文本文件并再次阅读

https://github.com/cynricfu/huffman-coding

#include <iostream>
#include <string>
#include <fstream>
#include <sstream> 
using namespace std;

//----------------------------READ IMAGE--------------------------------
void ReadImage(char fname[], int ***fimage, int& M, int& N, int& Q)
{
    int i, j;
    char d;

    char header [100], *ptr;
    ifstream ifp;

    ifp.open(fname, ios::binary);

    if (!ifp)
    {
        cout << "Can't read image: <" << fname << '>' << endl;
        void getch();
        exit(1);
    }

    ifp.getline(header,100,'\n');
    if((header[0]!='P') || header[1]!='5')   /* 'P5' Format */
    {
        cout << "Image <" << fname << "> is not in binary PGM 'P5' format." << endl;
        void getch();
        exit(1);
    }

    ifp.getline(header,100,'\n');
    while(header[0]=='#')
        ifp.getline(header,100,'\n');

    M=strtol(header,&ptr,0);
    N=atoi(ptr);

    ifp.getline(header,100,'\n');

    Q=strtol(header,&ptr,0);

    fimage = new int [N];
    for(i=0; i<N; i++)
        (*fimage)[i] = new int[M];

    for(i=0; i<N; i++)
    {
        for(j=0; j<M; j++)
        {
            d = ifp.get();
            (*fimage)[i][j]= (int)d;
            cout <<j;
        }
        cout <<i;
        }
    }
//-----------------------------Main-------------------------------------
int main()
{
    int i, j;
    int N, M, Q;        // N=Rows   M=Cols   Q=GreyLevels
    int **fimage;       // int **I 2-D Array of Image
    char infile[40];        // name of input file
    char outfile[40];   // name of output image file

    cout << "Enter name of *.pgm INPUT image file: ? ";
    cin  >> infile;
    cout << i<<endl;
    cout <<j<<endl;

    ReadImage(infile, &fimage, M, N, Q);    // Memory created for fimage
}

标签: c++imagehuffman-code

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