discord.py - 未定义的变量“公会”

Question

我试图制作一个 addrole 命令，但它不起作用。我收到错误：`undefined Variable 'guild' 我编写了代码 abc=guild.roles() 以列出服务器中的角色，但它不起作用请帮助

@client.command(pass_context=True) 
async def addrole(ctx, user: discord.Member, role: discord.Role): 
    if ctx.author.guild_permissions.administrator:
        xx=user.roles
        abc= guild.roles()
        if role in xx:
            if role in abc:
                 await user.add_roles(role)
                 await ctx.send(f'{user.mention}, {role} is given')
            else:
                 await ctx.send(f'The role you are looking for is not in the server')

        else:
             await ctx.send(f'The User already have the role')
    else:
         await ctx.send(f'You Have not enough permissions to run this command')

标签： discord.py

Answer 1

guild目前在您的范围内不存在。您需要一个discord.Guild对象才能获得其角色。

通过使用context，您可以获取发送命令的公会：

@client.command() # context is automatically passed in rewrite
async def addrole(ctx, user: discord.Member, role: discord.Role): 
    if ctx.author.guild_permissions.administrator:
        xx = user.roles
        abc = ctx.guild.roles
        if role in xx:
            if role in abc: # see footnote
                 await user.add_roles(role)
                 await ctx.send(f'{user.mention}, {role} is given')
            else:
                 await ctx.send('The role you are looking for is not in the server')
        else:
             await ctx.send('The User already have the role')
    else:
         await ctx.send('You Have not enough permissions to run this command')

# irrelevent check, as if the user has it, then it's guaranteed to be in the guild.
# Also, if it didn't exist, the command would error
# because the role needs to exist in the guild (discord.Role in arg types)
# in order for the command to execute

我还删除了不需要的 f 弦。它们用于格式化，因此f, 并且在某些地方你没有格式化字符串中的变量，所以我把它们拿出来了。

除此之外，到目前为止，您的代码看起来不错，请继续努力！

---

参考：

• f-string 用法- Python 3.6.0+
• 自动上下文传递
• commands.Context- 在命令的上下文中，您可以使用所有这些属性。它是第一个参数，通常命名为ctx.
• Context.guild
• Guild.roles- 注意它不是协程/函数，所以你不需要用括号来调用它()。在文档中，如果它是函数，您将在末尾看到括号，await如果是协程，则在前面看到括号。