首页 > 解决方案 > 编写一个循环遍历 to_ten 并打印出数字是偶数还是奇数

问题描述

to_ten=['1','2','3','4','5','6','7','8','9','10']

for i in range(10):

    if i %2==0:
        i='Number is even'
    else: i='Number is odd'
print(i)

创建一个名为 to_ten 的列表,其中包含 1-10 的数字。编写一个循环遍历 to_ten 并打印出该数字是偶数还是奇数。请帮助我了解如何为 1-10 列表中的每个数字说明它是偶数还是奇数。

标签: pythonfor-loop

解决方案


to_ten=['1','2','3','4','5','6','7','8','9','10']

for i in to_ten:
    if int(i)%2 == 0:
        print(f'{i} is even')
    else:
        print(f'{i} is odd')

出去:

1 is odd
2 is even
3 is odd
4 is even
5 is odd
6 is even
7 is odd
8 is even
9 is odd
10 is even

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