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json - 将两个相同文件的json文件合二为一

问题描述

我有这个版本的代码：我需要它来更改代码的某些部分或只是帮助我，因为我检查了谷歌中的所有链接。 

data, err := ioutil.ReadFile("firstfile.json")
    if err != nil {
        fmt.Print(err)
    }
    data1, err := ioutil.ReadFile("secondfile.json")
    if err != nil {
        fmt.Print(err)
    }
var migrations map[string]interface{}
var migrations1 map[string]interface{}

err = json.Unmarshal([]byte(data), &migrations)
err = json.Unmarshal([]byte(data1), &migrations1)

if err != nil {
    log.Println("Error:", err)
}
//fmt.Println(migrations)
//fmt.Println(migrations1)

mig := migrations["date"]
mig1 := migrations1["date"]

layout := "2006-01-02T15:04:05.000Z"
str := fmt.Sprint(mig)
str1 := fmt.Sprint(mig1)
t, err := time.Parse(layout, str)
t1, err := time.Parse(layout, str1)
if err != nil {
    fmt.Println(err)
}
//fmt.Println(t, t1)
firsthour := t.Hour()
secondhour := t1.Hour()

if firsthour == secondhour {
    result := []map[string]interface{}{}

    migrations3 := make(map[string]interface{})
    for k, v := range migrations {
        if _, ok := migrations[k]; ok {
            migrations3[k] = v
        }
    }

    for k, v := range migrations1 {
        if _, ok := migrations1[k]; ok {
            migrations3[k] = v
        }
    }

    result = append(result, migrations, migrations1)
    fmt.Println(result)
    b, err := json.Marshal(result)
    if err != nil {
        fmt.Println(err)
    }
    os.Stdout.Write(b)

} else {
    err = json.Unmarshal([]byte(data), &migrations)
    err = json.Unmarshal([]byte(data1), &migrations1)
    fmt.Println(migrations, migrations)
}

}

最后我得到了：

[{"data":"is nice",
  "date":"2012-04-23T18:24:59.511Z",
  "name":"Kate"},
 {"data":"is a good person",
  "date":"2012-04-23T18:25:00.511Z",
  "name":"Gleison"}]

但我想得到什么：

{
    "name":["kate","gleison"],
    "date":"2012-04-23T18:00:00.000Z",
    "data":["is nice","is a good person"]
}

你能帮我改变我的代码的某些部分来修复它吗？

我的 2 个 json 文件：

 {
        "name":"Kate",
        "date":"2012-04-23T18:24:59.511Z",
        "data":"is nice"
    },
 {
    "name":"Gleison",
    "date":"2012-04-23T18:25:00.511Z",
    "data":"is a good person"
}

标签： jsongo

解决方案

migrations, migrations1 := make(map[string]interface{}), make(map[string]interface{})

data := `{ "name":"Kate", "date":"2012-04-23T18:24:59.511Z", "data":"is nice" }`
data1 := `{ "name":"Gleison", "date":"2012-04-23T18:25:00.511Z", "data":"is a good person" }`

err := json.Unmarshal([]byte(data), &migrations)
if err != nil {
    panic(err)
}

err = json.Unmarshal([]byte(data1), &migrations1)
if err != nil {
    panic(err)
}

layout := "2006-01-02T15:04:05.000Z"

t, err := time.Parse(layout, fmt.Sprint(migrations["date"]))
t1, err := time.Parse(layout, fmt.Sprint(migrations1["date"]))
if err != nil {
    fmt.Println(err)
}

firsthour := t.Hour()
secondhour := t1.Hour()

if firsthour == secondhour {
    result := make(map[string][]interface{})

    for k, v := range migrations {
        result[k] = append(result[k], v)
    }

    for k, v := range migrations1 {
        result[k] = append(result[k], v)
    }

    fmt.Println(result)

    b, err := json.Marshal(result)
    if err != nil {
        fmt.Println(err)
    }

    os.Stdout.Write(b)

} else {
    err = json.Unmarshal([]byte(data), &migrations)
    if err != nil {
        panic(err)
    }

    err = json.Unmarshal([]byte(data1), &migrations1)
    if err != nil {
        panic(err)
    }

    fmt.Println(migrations, migrations)
}

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