时间戳

首页 > 解决方案 > 手机上的Unity鼠标输入

c# - 手机上的Unity鼠标输入

问题描述

我是新手Unity，我正在制作第一人称游戏。我关注了这个视频https://youtu.be/_QajrabyTJc，当我尝试使用UnityRemote 5 并且相机没有旋转时。代码在这里：

     public float mouseSensitivity = 100f;

    public Transform playerBody;

    float xRotation = 0f;


    void Update()
    {
        float mouseX = Input.GetAxis("Mouse X") * mouseSensitivity * Time.deltaTime;
        float mouseY = Input.GetAxis("Mouse Y") * mouseSensitivity * Time.deltaTime;



        xRotation -= mouseY;
        xRotation = Mathf.Clamp(xRotation, -90f, 90f);

        transform.localRotation = Quaternion.Euler(xRotation, 0f, 0f);
        playerBody.Rotate(Vector3.up * mouseX);

    }

我怎么解决这个问题？或者仅仅是因为我使用的是 Unity Remote 5，而不是 Android 手机？

标签： c#androidunity3dinput

解决方案

对于移动设备上的触摸输入，您宁愿使用Input.touches并执行类似的操作

// I would use a Vector2 here in order to be able
// to have a different sensitivity for the two axis
public Vector2 mouseSensitivity = Vector2.one * 100f;
public Transform playerBody;

private Vector2 startPos;
private float startRot;
private Quaternion originalBodyRot;

void Update()
{
    if(Input.touchCount == 1)
    {
        var touch = Input.GetTouch(0);

        switch(touch.phase)
        {
            case TouchPhase.Began:
                startPos = touch.position;
                startRot = transform.localEulerAngles.x;
                originalBodyRot = playerBody.rotation;
                break;

            case TouchPhase.Moved:
                var delta = Vector2.Scale(touch.position - startPos, mouseSensitivity);

                var newRot = Mathf.Clamp(startRot - delta.y, -90, 90);
                transform.localEulerAngles = new Vector3 (newRot, 0, 0);

                playerBody.rotation = originalBodyRot * Quaternion.Euler(0, delta.x, 0);            
                break;
        }
    }
}

请注意，touch.position它位于像素空间中，因此您可能需要调整灵敏度。

注意：在智能手机上输入，但我希望这个想法很清楚

推荐阅读