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python - 使用 RASA 的 API 的正确方法是什么（rasa.core.processor - 遇到异常）？

问题描述

我安装了 rasa-demo 代码示例。为了打开 rasa API，我做了：

user@User:~/rasa-demo ‹master*›$ rasa run
No chat connector configured, falling back to the REST input channel. To connect your bot to another channel, read the docs here: https://rasa.com/docs/rasa/user-guide/messaging-and-voice-channels
2020-06-19 13:20:02 INFO     root  - Starting Rasa server on http://localhost:5005
2020-06-19 13:20:08 INFO     absl  - Using /var/folders/h5/9rj1zn8x4s59bk_mg_ktzv740000gn/T/tfhub_modules to cache modules.
2020-06-19 13:20:08 INFO     absl  - Downloading TF-Hub Module 'http://models.poly-ai.com/convert/v1/model.tar.gz'.
2020-06-19 13:20:26 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 22.35MB
2020-06-19 13:20:43 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 42.35MB
2020-06-19 13:21:02 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 82.35MB
2020-06-19 13:21:21 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 118.59MB
2020-06-19 13:21:40 INFO     absl  - Downloading http://models.poly-ai.com/convert/v1/model.tar.gz: 148.59MB
2020-06-19 13:21:41 INFO     absl  - Downloaded http://models.poly-ai.com/convert/v1/model.tar.gz, Total size: 152.02MB
2020-06-19 13:21:41 INFO     absl  - Downloaded TF-Hub Module 'http://models.poly-ai.com/convert/v1/model.tar.gz'.
2020-06-19 13:22:14 INFO     root  - Rasa server is up and running.

如何将聊天机器人作为 API 进行查询？我希望能够提出请求并通过请求进行对话，而不是使用 shell。到目前为止，当我尝试对 rasa 服务器进行 curl 操作时：

在：

user@User:~ $ curl -XPOST localhost:5005/webhooks/rest/webhook -d '{"message":"hi"}'

出去：

[]%

在 rasa 运行服务器上，我得到以下响应：

2020-06-19 13:23:17 ERROR    rasa.core.actions.action  - Failed to run custom action 'action_greet_user'. Couldn't connect to the server at 'http://localhost:5055/webhook'. Is the server running? Error: Cannot connect to host localhost:5055 ssl:default [Connection refused]
2020-06-19 13:23:17 ERROR    rasa.core.processor  - Encountered an exception while running action 'action_greet_user'. Bot will continue, but the actions events are lost. Please check the logs of your action server for more information.
2020-06-19 13:24:04 ERROR    rasa.core.actions.action  - Failed to run custom action 'action_greet_user'. Couldn't connect to the server at 'http://localhost:5055/webhook'. Is the server running? Error: Cannot connect to host localhost:5055 ssl:default [Connection refused]
2020-06-19 13:24:04 ERROR    rasa.core.processor  - Encountered an exception while running action 'action_greet_user'. Bot will continue, but the actions events are lost. Please check the logs of your action server for more information.

它不工作。将 Rasa 服务器作为 API 请求的正确方法是什么？阅读文档后，我不清楚如何正确使用 API。

我也试过这个：

在：

import requests

response = requests.get('http://localhost:5005/webhooks/rest/webhook') 
print(response) 
print(response.headers) 
print(response.content)

出去：

<Response [405]>
{'Connection': 'keep-alive', 'Keep-Alive': '5', 'Allow': 'POST', 'Access-Control-Allow-Credentials': 'true', 'Content-Length': '60', 'Content-Type': 'text/plain; charset=utf-8'}
b'Error: Method GET not allowed for URL /webhooks/rest/webhook'

标签： pythonnlppython-requestsrasa-corerasa

解决方案

我最终弄清楚这就是您请求终点的方式：

localhost:5005/model/parse -s -d '{ "text": "hi" }'

文档应该更清楚。

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