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java - 查询路径变量时出现内部服务器错误 jdbc

问题描述

我有下面的代码，运行时出现以下错误。String转换似乎存在某种问题VARCHAR。

curl -v localhost:8080/trainer/Rach
*   Trying ::1...
* TCP_NODELAY set
* Connected to localhost (::1) port 8080 (#0)
> GET /trainer/Rach HTTP/1.1
> Host: localhost:8080
> User-Agent: curl/7.55.1
> Accept: */*
>
< HTTP/1.1 500
< Content-Type: application/json
< Transfer-Encoding: chunked
< Date: Wed, 17 Jun 2020 12:43:21 GMT
< Connection: close
<
{"timestamp":"2020-06-17T12:43:21.205+0000","status":500,"error":"Internal Server Error","message":"StatementCallback; bad SQL grammar [SELECT * fr
om TRAINERS where NAME=Rach]; nested exception is org.h2.jdbc.JdbcSQLSyntaxErrorException: Column \"RACH\" not found; SQL statement:\nSELECT * from
 TRAINERS where NAME=Rach [42122-200]","path":"/trainer/Rach"}* Closing connection 0

控制器：

 @GetMapping("/trainer/{trainer_name}")
    public Trainer getTrainer(@PathVariable String trainer_name) {
       Trainer t = jdbcTemplate.queryForObject("SELECT * from TRAINERS where NAME=" + trainer_name , new 
                   TrainerRawMapper());
       return t;
    }

原始映射器：

public class TrainerRawMapper implements RowMapper<Trainer> {
    @Override
    public Trainer mapRow(ResultSet rs, int rowNum) throws SQLException {
        Trainer trainer = new Trainer();
        trainer.setName(rs.getString("NAME"));
        trainer.setLevel(rs.getInt("LEVEL"));
        trainer.setBag(new Stack<Pokemon>());

        return trainer;
    }
}

数据：

CREATE TABLE TRAINERS (NAME VARCHAR(225) PRIMARY KEY,
                        LEVEL INT)

-- TRAINERS insertions

INSERT INTO TRAINERS (NAME,LEVEL) VALUES ('Rach',8);
INSERT INTO TRAINERS (NAME,LEVEL) VALUES ('Rache',0);
INSERT INTO TRAINERS (NAME,LEVEL) VALUES ('Rachel',1);
INSERT INTO TRAINERS (NAME,LEVEL) VALUES ('Racheli',2);

标签： javaspringjdbch2spring-jdbc

解决方案

更新查询并放置trainer_name不带引号的内容，如下所示：

String sql = "SELECT * from TRAINERS where NAME = '" + trainer_name +"'";
Trainer t = jdbcTemplate.queryForObject(sql, new TrainerRawMapper());

解决方案只是为了纠正错误。

,出于安全原因，最好使用 jdbcTemplate 来替换值，以避免 SQL 注入等 SQL 攻击

String sql = "SELECT * from TRAINERS where NAME = ?";
return jdbcTemplate.queryForObject(sql, new Object[]{trainer_name}, new TrainerRawMapper());

Spring Doc::queryForObject

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