excel - 如何将新工作表保存到现有 Excel 工作簿的开头?
问题描述
我从这篇文章中找到了部分答案,它非常有用 https://stackoverflow.com/a/42375263/13765378
但是,每次我使用新数据运行此代码时,都会在工作簿的末尾添加一个新工作表。过了一会儿,要找到刚刚添加的新工作表是相当困难的。有没有办法指定添加到工作簿的开头,所以当我们打开工作簿时它将是默认工作表?
解决方案
感谢 Vignesh 的回答,感谢并修改了 将 pandas 数据框写入现有工作簿 的代码,我得到了以下代码:[每次运行程序时,都会在工作簿的开头创建一个新工作表并包含(新数据。其余代码只是测试函数 append_df_to_excel()] 函数 append_df_to_excel() 似乎对我需要做的事情太过分了,但现在我找不到更好、更干净的方法来做这件事。
我也不明白为什么最后保存工作簿不会保存数据。
import os
from openpyxl import load_workbook
import xlsxwriter
import pandas as pd
from datetime import datetime
filename = r'C:\test\test.xlsx'
if not os.path.exists(filename):
wb = xlsxwriter.Workbook(filename)
wb.close()
def append_df_to_excel(filename, df, sheet_name='Sheet1', startrow=None,
truncate_sheet=False,
**to_excel_kwargs):
"""
Append a DataFrame [df] to existing Excel file [filename]
into [sheet_name] Sheet.
If [filename] doesn't exist, then this function will create it.
Parameters:
filename : File path or existing ExcelWriter
(Example: '/path/to/file.xlsx')
df : dataframe to save to workbook
sheet_name : Name of sheet which will contain DataFrame.
(default: 'Sheet1')
startrow : upper left cell row to dump data frame.
Per default (startrow=None) calculate the last row
in the existing DF and write to the next row...
truncate_sheet : truncate (remove and recreate) [sheet_name]
before writing DataFrame to Excel file
to_excel_kwargs : arguments which will be passed to `DataFrame.to_excel()`
[can be dictionary]
Returns: None
"""
# ignore [engine] parameter if it was passed
if 'engine' in to_excel_kwargs:
to_excel_kwargs.pop('engine')
writer = pd.ExcelWriter(filename, engine='openpyxl')
if not os.path.exists(filename):
wb = xlsxwriter.Workbook(filename)
wb.close()
try:
# try to open an existing workbook
writer.book = load_workbook(filename)
# get the last row in the existing Excel sheet
# if it was not specified explicitly
if startrow is None and sheet_name in writer.book.sheetnames:
startrow = writer.book[sheet_name].max_row
# truncate sheet
if truncate_sheet and sheet_name in writer.book.sheetnames:
# index of [sheet_name] sheet
idx = writer.book.sheetnames.index(sheet_name)
# remove [sheet_name]
writer.book.remove(writer.book.worksheets[idx])
# create an empty sheet [sheet_name] using old index
writer.book.create_sheet(sheet_name, idx)
# writer.book.create_sheet(sheet_name, 0) #not working
# copy existing sheets
writer.sheets = {ws.title:ws for ws in writer.book.worksheets}
except FileNotFoundError:
# file does not exist yet, we will create it
pass
if startrow is None:
startrow = 0
# write out the new sheet
df.to_excel(writer, sheet_name, startrow=startrow, **to_excel_kwargs)
# save the workbook
writer.save()
A = [[0,1,2],[3,4,5],[6,7,8],[9,10,11]]
df = pd.DataFrame(A, columns=list('XYZ'))
newSheet = "New_" + datetime.now().strftime('%Y-%m-%d_%H%M%S')
wb = load_workbook(filename)
ws = wb.create_sheet(newSheet, 0)
wb.save(filename)
append_df_to_excel(filename, df, sheet_name="Old2", startrow=1, startcol=1)
append_df_to_excel(filename, df, sheet_name="Old3", index=False)
append_df_to_excel(filename, df, sheet_name="Old1", startcol=2, index=False)
append_df_to_excel(filename, df, sheet_name=newSheet, columns=df.columns.values, startrow=0, startcol=0, index=False)
# wb.save(filename) # Do not do this, will get nothing written to workbook
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