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javascript - 来自其他站点时如何自动打开选项卡？

问题描述

目前我有一个带有元素表的站点。这些元素有一些子元素。我有第二个站点，我可以在其中看到元素和子元素的许多选项卡。我现在以这种方式调用该网站：

<a class="dropdown-item" role="presentation" asp-controller="Scenario" asp-action="SimulationEvaluation">Auswerten</a>

所以元素是模拟，子元素是模拟的结果。第二页中的选项卡和功能如下所示：

<div class="tab" style=" border: none; overflow:hidden">
                <button class="tablinks" onclick="openTab(event, 'Ergebnis-1')" id="defaultOpen">Ergebnis-1</button>
                <button class="tablinks" onclick="openTab(event, 'Ergebnis-2')">Ergebnis-2</button>
                <button class="tablinks" onclick="openTab(event, 'Ergebnis-3')">Ergebnis-3</button>
            </div>

<div id="Ergebnis-1" class="tabcontent">
    ......
</div>
<div id="Ergebnis-2" class="tabcontent">
    ......
</div>
<div id="Ergebnis-3" class="tabcontent">
    ......
</div>

<script>

    document.getElementById("defaultOpen").click();

    function openTab(evt, name) {
        // Declare all variables
        var i, tabcontent, tablinks;

        // Get all elements with class="tabcontent" and hide them
        tabcontent = document.getElementsByClassName("tabcontent");
        for (i = 0; i < tabcontent.length; i++) {
            tabcontent[i].style.display = "none";
        }

        // Get all elements with class="tablinks" and remove the class "active"
        tablinks = document.getElementsByClassName("tablinks");
        for (i = 0; i < tablinks.length; i++) {
            tablinks[i].className = tablinks[i].className.replace(" active", "");
        }

        // Show the current tab, and add an "active" class to the button that opened the tab
        document.getElementById(name).style.display = "block";
        evt.currentTarget.className += " active";
    }
</script>

我现在的问题是：当我单击第一页表格中的子元素时，我希望自动打开匹配的选项卡。因此，当我单击 Simulation-1，Result-3 示例时，我希望预先打开 Result-3-Tab。那可能吗？^^

标签： javascripthtml

解决方案

In the first site you have to set up links like this

<a href="secondsite.com?tab=Simulation-1">Simulation-1</a>
<a href="secondsite.com?tab=Result-3">Result-3</a>

And in the second website you have to add this javascript code inside document.ready:

const urlParams = new URLSearchParams(window.location.search);
const tabName = urlParams.get('tab');

if (tabName){
 document.querySelector('[onclick*=' + tabName + ']').click();
}

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