javascript - 如何匹配对象的多个属性

Question

我可以很容易地匹配一个属性

var peoples = [
  { "name": "bob", "dinner": "pizza" },
  { "name": "john", "dinner": "sushi" },
  { "name": "larry", "dinner": "hummus" },
  { "name": "john", "dinner": "pie" }
];

$.each(peoples, function(i, val) {
    $.each(val, function(key, name) {
        if (name === "john")
            console.log(key + " : " + name);
       });
});

但是由于有 2 个 john，我如何匹配一个特定的（例如，喜欢寿司的 john）然后返回整个匹配的对象（在 json 中）？我尝试在 if 语句中添加另一个条件，但这似乎不起作用。

谢谢

标签： javascriptjquery

Answer 1

你可以find用来检查完全匹配

var peoples = [
  { "name": "bob", "dinner": "pizza" },
  { "name": "john", "dinner": "sushi" },
  { "name": "larry", "dinner": "hummus" },
  { "name": "john", "dinner": "pie" }
];

var filteredResult = peoples.find(val => val.name ==="john" && val.dinner==="sushi");
console.log(filteredResult)