python - 在 Python 中将定义的函数转换为 lambda 函数

Question

我一直在尝试将以下函数转换为 lambda 函数：

def cars(manf, model_name, **car_info):
    """Build a dictionary storing information about a car"""
    car_info['manufacturer'] = manf
    car_info['model'] = model_name
    return car_info

这是我的尝试：

cars=(lambda manf, model_name,**car_info: car_info['manufacturer']=manf car_info['model']=model_name))

在这里我得到这个错误：

cars=(lambda manf, model_name,**car_info: car_info['manufacturer']=manf car_info['model']=model_name)
                                                                      ^
SyntaxError: invalid syntax

和

cars=(lambda manf, model_name,**car_info: car_info.where(car_info['manufacturer']=manf, car_info['model']=model_name))

在这里我得到这个错误：

cars=(lambda manf, model_name,**car_info: car_info.where(car_info['manufacturer']=manf, info['model']=model_name))
                                                            ^
SyntaxError: keyword can't be an expression

有没有办法将这种函数转换为 lambda？

标签： pythonpython-3.xfunctionlambda