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spring - Spring引导数据jpa @Query本机查询的单元测试用例是否可能？

问题描述

我有一个配置了 JPA 的 Spring Boot 应用程序。在查询数据库时，我在 spring data @query 注释的帮助下运行本机 sql 查询。现在我打算使用 Spring Boot 测试框架编写测试用例。是否可以编写测试？

代码：

String searchQuery = "SELECT dh1.* FROM device_hist AS dh1 JOIN (" +
        "SELECT rank() OVER (PARTITION BY dh.device_nm, dh.lst_log_in_user_id ORDER BY lst_chkin_ts DESC), " +
        "dh.device_nm, dh.lst_log_in_user_id, dh.lst_chkin_ts FROM device_hist dh) AS T ON dh1.device_nm = T.device_nm " +
        "AND dh1.lst_log_in_user_id = T.lst_log_in_user_id AND dh1.lst_chkin_ts = T.lst_chkin_ts WHERE T.rank = 1 AND " +
        "dh1.lst_chkin_ts >= :lst_chkin_ts ";

String searchCountQuery = "SELECT count(*) FROM device_hist AS dh1 JOIN (" +
        "SELECT rank() OVER (PARTITION BY dh.device_nm, dh.lst_log_in_user_id ORDER BY lst_chkin_ts DESC), " +
        "dh.device_nm, dh.lst_log_in_user_id, dh.lst_chkin_ts FROM device_hist dh) AS T on h1.device_nm = T.device_nm " +
        "AND dh1.lst_log_in_user_id = T.lst_log_in_user_id AND dh1.lst_chkin_ts = T.lst_chkin_ts WHERE T.rank = 1 " +
        "AND dh1.lst_chkin_ts >= :lst_chkin_ts ";

@Query(value = searchQuery + "ORDER BY dh1.device_nm, dh1.lst_chkin_ts DESC",
        countQuery = searchCountQuery,
        nativeQuery = true)
Page<DeviceHistory> findAllLatestDeviceHistoryBylastCheckInTimeStamp(
        @Param("lst_chkin_ts") Date lastCheckInTimeStamp, Pageable pageable);

测试用例：

@Test
void testfindAllLatestDeviceHistoryBylastCheckInTimeStamp() {
    LocalDate localDateTime = LocalDate.now();
    ZoneId defaultZoneId = ZoneId.systemDefault();

    Instant instant = localDateTime.minusDays(10).atStartOfDay(defaultZoneId).toInstant();
    Date timeStamp =  Date.from(instant);
    Page<DeviceHistory> devices = deviceHistoryRepository.findAllLatestDeviceHistoryBylastCheckInTimeStamp(timeStamp, pageable);

    assertNotNull(devices.getContent());
}

错误：

无法提取结果集；SQL [不适用]；嵌套异常是 org.hibernate.exception.SQLGrammarException: could not extract ResultSet org.springframework.dao.InvalidDataAccessResourceUsageException: could not extract ResultSet; SQL [不适用]；嵌套异常是 org.hibernate.exception.SQLGrammarException: could not extract ResultSet at org.springframework.orm.jpa.vendor.HibernateJpaDialect.convertHibernateAccessException(HibernateJpaDialect.java:281) at org.springframework.orm.jpa.vendor.HibernateJpaDialect.translateExceptionIfPossible (HibernateJpaDialect.java:255) 位于 org.springframework.dao.support.ChainedPersistenceExceptionTranslator.translateExceptionIfPossible(ChainedPersistenceExceptionTranslator.java:61) 的 org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.translateExceptionIfPossible(AbstractEntityManagerFactoryBean.java:528)。

在 org.springframework.transaction.interceptor.TransactionAspectSupport.invokeWithinTransaction(TransactionAspectSupport.java:366) 在 org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:99) 在 org.springframework.aop.framework.ReflectiveMethodInvocation.proceed (ReflectiveMethodInvocation.java:186) at org.springframework.dao.support.PersistenceExceptionTranslationInterceptor.invoke(PersistenceExceptionTranslationInterceptor.java:139) ... 96 更多原因：org.postgresql.util.PSQLException：错误：缺少 FROM 子句条目表“h1”

标签： springspring-bootspring-data-jpaspring-testnative-sql

解决方案

我觉得你有问题

String searchCountQuery

异常告诉你你有一个叫做h1table的问题

ERROR: missing FROM-clause entry for table "h1"

据我所见，该字符串包含h1：“dh.device_nm, dh.lst_log_in_user_id, dh.lst_chkin_ts FROM device_hist dh) AS T on h1 .device_nm = T.device_nm ”。（我猜应该是dh1 ）

通常，如果您面临，SQLGrammarException: could not extract ResultSet那么它可能是您的 SQL 的问题。此外，堆栈跟踪的其余部分通常有助于澄清问题。

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