html - 阴影根的 css 选择器（关闭），python 3

Question

我想使用scrapy spider的css选择器从以下html中提取下一页url。

<button id="omni-next-click" name="searchnextclick" class="btn btn__blue btn__rounded" aria-label="next" data-reactid="971" omnivalue="1">
 <span class="icon icon__arrow-right" data-reactid="972">
  <svg aria-hidden="true" data-reactid="973">
   <use xlink:href="/images/adaptive/livestyleguide/walgreens.com/v3.0/themes/images/icons/symbol-defs.svg#icon__arrow-right" data-reactid="974">
    #shadow-root (closed)
     <svg id="icon__arrow-right" viewBox="0 0 32 32">
       <title>icon__arrow-right</title>
       <path d="M13.312 21.952c-0.144 0-0.288-0.064-0.4-0.176-0.224-0.224-0.224-0.592 0-0.816l4.976-4.976-4.976-4.96c-0.224-0.224-0.224-0.592 0-0.816s0.592-0.224 0.816 0l5.376 5.376c0.224 0.224 0.224 0.592 0 0.816l-5.376 5.376c-0.128 0.112-0.272 0.176-0.416 0.176z">
       </path>
     </svg>
   </use>
  </svg>
 </span>
</button>

我是新手。请帮助我完成它。如何找到 css 以便可以爬取所有可用页面？

标签： htmlcsspython-3.xscrapycss-selectors