首页 > 解决方案 > 向对象数组中的对象添加元素Javascript

问题描述

问题很简单。我尝试了很多次,因此我在stackoverflow中寻求帮助。我有一个名为 data 的对象数组,它是从 mongodb 数据库返回的数据。格式类似于:

 let data = [
{ booking: [ ref], max_booking: 0 },
{ booking: [ref], max_booking: 3 },
{ booking: [ref], max_booking: 5 },
{booking: [ref], max_booking: 4}
];

根据请求,我添加了来自我的数据库的真实数据:

[ { booking: [],
_id: null,
__v: 0,
comment: 'this is a comment',
date: 2020-07-26T00:00:00.000Z,
event_detail: 'this is event detail',
location: 'Kthm',
max_booking: 5,
meal_option: [ [Object] ],
sponsor_address: 'xxxx',
sponsor_name: 'yyyy',
id: null },
{ booking: [],
_id: 5ef60fab6c164281aee9ae2e,
date: 2020-07-30T00:00:00.000Z,
location: 'Kthm',
comment: 'this is another',
sponsor_name: 'Micorosft',
sponsor_address: 'USA',
event_detail: 'this is event detail',
meal_option: [ [Object] ],
max_booking: 5,
__v: 0,
id: '5ef60fab6c164281aee9ae2e' },
{ booking: [],
_id: 5ef6131f6c164281aee9ae30,
date: 2020-07-30T00:00:00.000Z,
location: 'TAN TOCK SENG HOSPITAL',
comment: 'this is dsadasdas',
sponsor_name: 'Asus',
sponsor_address: 'Los Angeles, USAssadsad',
event_detail: 'this is event detail',
meal_option: [ [Object] ],
max_booking: 5,
__v: 0,
id: '5ef6131f6c164281aee9ae30' },

]

我想执行如下操作:当 max_booking 与任何对象上的预订数组长度匹配时,应将新元素添加到该特定对象中。

{booking:[lets assume 5], max_booking: 5, result:1}

如果如果预订仍然少于还应该添加一个新元素但结果为 0 像

{booking:[lets asssume 3], max_booking:5, result:0}

要执行此操作,我所做的是:

    data.map((d, i) => {
     if (d.booking.length === d.max_booking) {
      console.log("Fully Booked in index", i);
       d.result = 1;
     } else {
       console.log("Not booked");
       d.result = 0;
      }
      console.log(d.result);
    });
  console.log(data[3]);

让我们暂时忽略 else 应该小于符号。foreach 循环中 d.result 的值打印在控制台上,但是当我记录数据时,根本没有任何改变。任何人都可以帮助我。提前致谢。

代码截图: 在此处输入图像描述

输出截图: 输出

标签: javascriptnode.jsarrays

解决方案


为什么人们要放弃一个简单的 for 循环?

for(var i=0;i<data.length;i++) {
     if (data[i].booking.length === data[i].max_booking) {
       console.log("Fully Booked in index", i);
       data[i].result = 1;
     } else {
       console.log("Not booked");
       data[i].result = 0;
     }
}
console.log(data.result);

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